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frutty [35]
2 years ago
12

The construction of a tangent to a circle given a point outside the circle can be justified using the second corollary to the in

scribed angle theorem. An alternative proof of this construction is shown below. Complete the proof

Mathematics
2 answers:
romanna [79]2 years ago
6 0

Answer:

Step 3 Reason: If in a triangle two sides are equal, then it is an Isosceles Triangle.

Step 4 Reason: The Sum of interior angles of Triangle is 180°.

Statement of Step 5: Isosceles Triangle Theorem states that ,the two equal sides of Isosceles triangle have equal opposite angles.

Reason for step 9: Addition Subtraction Property

Reason for step 10: ∠ADC and ∠EDA, lie on a straight line,CE.Also, AD is a ray,through point D.

Statement for Step 11: Linear pair Postulate states that,the two angles which are adjacent of a common ray on a line have the sum 180°.

Reason for step 16: Dividing both sides by -2.

Statement for step 18: ∵ m∠CAE=90°

Statement for step 20: CA ⊥ AE

Reason for step 21: If the angle between radius and the point of contact of a line or line segment which  passes through the end of segment of  radius which lies on circle is of 90°, then that line is tangent to the circle.

ladessa [460]2 years ago
3 0
3)AD = CD = The radius o the circle. 
AD = DE = The radius o the greatest circle. 
4)The sum of the angles of any triangle equate is 180 degrees. 
5)Measure DCA = Measure CAD, Measure DAE = Measure AED.
9)Statment 8.  
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harina [27]
In order to make this easier, let us convert the fraction into a mixed number. 2 2/3 would become 8/3. Now, let us divide 8 pints by 8/3 cups and we get 24/8 or 3 cups. Therefore, the amount of water that Cary has to use when she makes barbecue sauce with 1 pint of tomato is 3 cups. 
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2 years ago
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If the number of concerts held in a city is correlated to the number of local radio channels, what third variable might most lik
Alekssandra [29.7K]
Are there choices for this question? If not ,then the possible third variable that might most likely be responsible for the correlation between the number of concerts held in a city and number of local radio channels would be the number of radio channel listeners (since concerts and radio channels both are related to music).
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2 years ago
Samin can run 5 kilometers in 30 minutes. Assuming she keeps a constant pace, how many kilometers can she run in 45 minutes? URG
bulgar [2K]

Answer:

7.5kilometer

Step-by-step explanation:

for 30mins semin runs 5kilometer

then for 1min: (1min×5kilometer)÷30mins,

therefore, for 45mins: (45mins×5kilometer)÷30mins=7.5kilometer

3 0
2 years ago
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PLEASE HELP ME ASAP !!! JUST ANSWER ONE OR BOTH PLEASE HELP!!
Sliva [168]
Use equation A=P(1-r)^{t}

Question 1: Need to find A:
A=370,000(1-0.043)^{11} =228157.

Question 2: Need to find t, use LOGARITHM:
1-r=1-0.0106=0.9894 \\ log( \frac{A}{P})=tlog(0.9894)
A=35000
P=49339
\frac{A}{P}=0.7093779769 \\  \frac{log(0.7093...)}{log(0.9894}  =t
32.221104307=t=32years.
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8 0
2 years ago
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The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda
blondinia [14]

Answer:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

\mu = 514 , \sigma =40

For this case we can use the Chebysev theorem who states that "At least 1 -\frac{1}{k^2} of the values lies between \mu -k\sigma and \mu +k\sigma"

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

4 0
2 years ago
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