A Student Who Is 60 Inches Tall Measured Shadows To Find The Height Of A Tree. The Students Shadow Was 24 Inches Long, And The S
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Answer:
See below
Step-by-step explanation:
This graph could describe a relay race.
Jamie writes a scenario that can be modeled by the piecewise function on the graph.
The graph has time, in minutes on the x-axis and the distance, in miles on the y-axis.
The first part of the graph is the line starting from the origin through to the point (12, 1) then the second part starts from the point (12, 1) and ends on the point (20, 2).
1. A runner begins the race and runs at a steady pace for 1 minute.
- This is incorrect as describes the wrong axis.
It should say: a runner begins a race and runs at a steady pace for 12 minutes, completing 1 mile distance.
<u>The equation for this part:</u>
- y = mx + b
- b = 0 as it starts at origin.
- m = 1/12
- y = 1/12x
- x = [0, 12], y = [0, 1]
2. His partner then takes over and runs at a steady, but faster, pace for another 1 minute.
- Again, as above, wrong axis is described.
It should say: his partner then takes over and runs at a steady, but faster, pace for another 8 minutes, completing the last 1 mile of the race.
<u>The equation for this part:</u>
- b =1, as a starting point
- m = (2-1)/(20-12) = 1/8
- y = 1/8x + 1
- x = (12, 20], y = (1, 2]
Answer:
<h3>AC=96 units.</h3>Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get
Subtracting 6x from both sides, we get
Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>