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Delicious77 [7]
2 years ago
12

PLZZZZZZ HELP ME WITH 10 QUESTIONS PLZZ Stefan is measuring the angles of a triangle. He measures the first angle and gets a mea

sure of 90°. What does he know about the other two angles? A) They are each 45°. B) They should add up to be 270° C) Their measures should add up to be 90° D) He doesn't know anything about the other two angles. 2) Donny is measuring the angles of a triangle. He measures the first two angles and gets 30° and 100°. How could he find the measure of the third angle? A) Subtract 100 and 30 from 180 since the three angles should sum up to 180°. B) Subtract 100 and 30 from 360 since the three angles should sum up to 360°. C) Add 100 and 30 since the third angle should be the sum of the first two angles. D) Add 100 and 30 and then double it since the third angle should be twice the sum of the first two. 3) Find m∠P in the diagram. A) 50 degrees B) 100 degrees C) 110 degrees D) 130 degrees 4) In trapezoid ABCD, find m∠A if m∠B= 25°, m∠C = 155° and m∠ D= 117°. A) 25°
Mathematics
1 answer:
GREYUIT [131]2 years ago
4 0
Next time you post a question, break it up into a couple of questions. If you don't want to do that use paragraphs and finally, if that doesn't suit you add more points -- Please. No offense intended. the please is genuine.

1.  A triangle = 180o. If one is 90, the other 2 will be a total of 90o
Answer C: <<<====

2. A looks like the correct answer. 30 + 100 = 130 ; 180 - 130 = 50

3. You need a diagram to get the third one.
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What is the difference between 4Σn=1, 2n+1 and 4Σi=1, (2i+1)?
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2 years ago
You and your neighbor attempt to use your cordless phones at the same time. Your phones independently select one of ten channels
ExtremeBDS [4]

Answer:

1/100.

Step-by-step explanation:

So, we can make the following deductions from the information given in the question or problem above.

[1]. "You and your neighbor attempt to use your cordless phones at the same time."

DEDUCTION: Two people are involved, that is you and your neighbor are both involved.

[2]. "Your phones independently select one of ten channels at random to connect to the base unit. "

DEDUCTION: Both cordless phones can choose one channels each which is random. The number of channels available is ten.

Therefore, the probability that both your phone and your neighbor phone pick the same channel can be calculated or determined as follows:

The probability that both your phone and your neighbor phone pick the same channel = probability that both your phone will pick one channel out of the ten channels ×  the probability that your neighbor phone pick one channel out of the ten channels.

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8 0
2 years ago
A customer visiting the suit department of a certain store will purchase a suit with probability .22, a shirt with probability .
BigorU [14]

Answer:

a) The probability that he doesnt but any items is 0.49

b) He buys exactly 1 of those items with probability 0.28

Step-by-step explanation:

lets call su the event that the customer purchases a suit, sh the event that teh customer purchases a shirt and t the event that the customer purchases a tie.

Remembe that for events A, B and C we have that

P(A U B) = P(A) + P(B) - P(A ∩ B)

P(A U B U C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

Also, we are given that

P(su) = 0.22

P(sh) = 0.3

p(t) = 0.28

p(su ∩ sh) =  0.11

P(su ∩ t) = 0.14

P(sh ∩ t) = 0.1

P(sh ∩ t ∩ su) = 0.06

The event that he doesnt buy any item has as complementary event su ∪ sh ∪ t, therefore

P( he doesnt but any items) = 1-P(su U sh U t) =

1-( P(su) + p(sh) + p(t) - P(su ∩ sh) - p(su∩t) - p(sh∩t) + p(su∩sh∩t) ) =

1-(0.22+0.30+0.28-0.11-0.14-0.1+0.06) = 1-0.51 = 0.49

b) The probability that he buys at least 2 items is equal to

p(su ∩ t) + p(su ∩ sh) + p(sh ∩ t) -2 p(su ∩ t ∩ sh) (because we are counting the triple intersection 3 times, so we need to remove it twice)

This number is

0.14+0.11+0.1-2*0.06 = 0.23

Thus, the probability that he buys exactly one item can be computed by substracting from one the probability of the complementary event : she buys 2 or more or non items

P(he buys exactly one item) = 1- ( p(he buys none items) + p(he buys at least 2) ) = 1- 0.49-0.23 = 0.28

7 0
2 years ago
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