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2 years ago

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Claire runs a rooftop nursery garden in the heart of the city. One day, she cuts 25 tulips, 32 violets, and 40 sunflowers. She s

ells the flowers to a local florist at t, v, and s dollars, respectively. Claire’s cost to grow the flowers is 10% less than the total selling price. Which expressions represent Claire’s cost to grow the flowers?(25t + 32v + 40s) + 0.10(25t + 32v + 40s) (25t + 32v + 40s) – 0.10(25t + 32v + 40s) 0.90(25t + 32v + 40s) 1.1(25t + 32v + 40s)

2 answers:

ad-work [718]2 years ago

7 0

I think it would be (25t+32v+40s) -0.10(25t+32v+40s)

ludmilkaskok [199]2 years ago

6 0

Answer:

The correct options are 2 and 3.

Step-by-step explanation:

It is given that Claire cuts 25 tulips, 32 violets, and 40 sunflowers. She sells the flowers to a local florist at t, v, and s dollars, respectively.

Total selling price is

$S.P.=25t+32v+40s$

It is given that Claire’s cost to grow the flowers is 10% less than the total selling price.

$C.P.=S.P.-10\%\text{ of S.P.}$

$C.P.=(25t+32v+40s)-\frac{10}{100}(25t+32v+40s)$

$C.P.=(25t+32v+40s)-0.10(25t+32v+40s)$

This expression is same as option 2. So, option 2 is correct.

Taking out the common factors.

$C.P.=(1-0.10)(25t+32v+40s)$

$C.P.=0.90(25t+32v+40s)$

This expression is same as option 3. So, option 3 is correct.

Therefore the correct options are 2 and 3.

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2 years ago

A 2-column table with 6 rows. The first column is labeled x with entries negative 1, 0, 1, 2, 3, 4. The second column is labeled

Rufina [12.5K]

Answer:

(2, 0)

Step-by-step explanation:

The only table entry with y = 0 is (x, y) = (2, 0). That is the x-intercept.

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2 years ago

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The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi

Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

$\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872$

From central limit theorem, we have:

$z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}$

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

$P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)$

$= 1 - P(z \leq 1.667)$

Calculation the value from standard normal z table, we have,

$P(x > 950) = 1 - 0.952 = 0.048$

0.048 is the probability that more than 950 message arrive in one minute.

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2 years ago

The Leaning Tower of Pisa in Italy was built between 1173 and 1350. A. Write an equation in slope-intercept form for the yellow

mote1985 [20]

Answer:

The answer is below

Step-by-step explanation:

From the image of the leaning tower of Pisa, we can see that it passes through the point (7.75, 0) and (10.75, 42).

a) The equation of a line in slope intercept form is given by y = mx + b, where m is the slope and b is the intercept. Also, the equation of line passing through

$(x_1,y_1)\ and\ (x_2,y_2)\ is:\\\\y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)$

Hence since it passes through (7.75, 0) and (10.75, 42), the equation is:

$y-0=\frac{42-0}{10.75-7.75} (x-7.75)\\\\y=14(x-7.75)\\\\y=14x-108.5$

b) When the tower is 56 meters tall, i.e. y = 56, we need to find the value of x:

y = 14x - 108.5

56 = 14x - 108.5

56 + 108.5 = 14x

164.5=14x

x = 164.5/14

x = 11.75

When the tower is 56 meters tall, the top of the tower is 11.75 m off center

5 0

2 years ago

Sarah’s stands on a ground and sights the top of a steep Clift at a 60 degree angle of elevation she then steps back 50 meters t

SashulF [63]

Answer:

Cliff is 45 m tall.

Step-by-step explanation:

Given:

Height of Sarah = 1.8 m

Angle of elevation = 60°

Angle of elevation 50 m back = 30°

As shown in the figure we have two right angled triangles SPQ and SPR.

Let the height of the cliff be $h$ meters and $h= h_1+h_s$ .

Using trigonometric ratios:

tan (Ф) = opposite/adjacent

In ΔSPQ. In ΔSPR.

⇒ $tan(60) = \frac{h_1}{x}$ ...equation (i) ⇒ $tan (30)=\frac{h_1}{x+50}$ ...equation (ii)

Dividing equation (i) and (ii)

⇒ $\frac{tan(60)}{tan(30)} = \frac{h_1}{x} \times \frac{x+50}{h_1}$

⇒ $3 = \frac{x+50}{x}$

⇒ $3x=x+50$

⇒ $3x-x=50$

⇒ $2x=50$

⇒ $x=\frac{50}{2}$

⇒ $x=25$ meters

To find $h_1$ plugging $x=25$ in equation (i)

⇒ $h_1=x\times tan(60)$

⇒ $h_1=25\times 1.73$

⇒ $h_1=43.25$ meters

The height of the cliff from ground :

⇒ $h= h_1+h_s$

⇒ $h= 43.25+1.8$

⇒ $h=45.05$ meters

The cliff is 45 m tall to the nearest meter.

8 0

2 years ago