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nydimaria [60]
2 years ago
9

Liam's bookstore sold 4 0 4040 notebooks and 2 0 2020 newspapers for a total of $ 1 3 0 $130dollar sign, 130. A day later, the b

ookstore sold 8 88 notebooks and 4 44 newspapers at the same prices, for a total of $ 2 8 $28dollar sign, 28.
Mathematics
1 answer:
EleoNora [17]2 years ago
8 0
Lets say that:
X = price of each notebook
Y = price of each newspaper
 
So from the problem statement we can create the following equations:
40 X + 20 Y = 130                               --> eqtn 1
8 X + 4 Y = 28                                      --> eqtn 2
 
Divide both equations by the lowest coefficient to simplify:
Divide eqtn 1 by 20 =>   2 X + Y = 6.5
Divide eqtn 2 by 4=>       2 X + Y = 7
 
So we can see that although both equations has equal left side, the right side do not match. Hence this problem is impossible to solve.
 
so the given information describes an impossible situation.
 
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During the summer, Abrielle is a cashier at a grocery store and Zane serves ice cream. To show their earnings, Abrielle makes a
disa [49]
The slope of Zane is 18.50/2 = 9.25

Subtract both slopes to find the true statement.

10.5 - 9.25 = 1.25

The correct statement is:

abrielle earns $1.25 more than zane.

Hope this helps :)
7 0
2 years ago
Read 2 more answers
A company makes 150 bags.
irina [24]
35% chance because the company made 150 bags
4 0
1 year ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
olivia purchases gifts for mothers day. thev first is a pair of sunglasses for $16.35 and the second is a bracelet . her total i
mash [69]

Answer:

$23.40

Step-by-step explanation:

You have to subtract $39.75 by $16.35 as $39.75 is the total and we have to find out how much the bracelet is. There is also no regrouping.

7 0
2 years ago
Round each weight to the nearest whole gram. Then estimate the total weight of the coins in Allen’s hand. 2.500,5.000,2.268,5.67
irina1246 [14]
So the rounded weights would be 3, 5, 2, 6, and 11, as when you round, you look at the number to the right of the one you want to round to. If it's 5 or larger, you add one to the spot you're rounding to, and make the rest of the numbers after into zeroes. If it's below 5, just change the ones after the one you want to round to into zeroes and don't add one.

Then for the estimating of the weight, you would add them together. 3+5+2+6+11. That would equal 27, so the estimate weight is 27 grams.
8 0
2 years ago
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