<span> If P(x) is a polynomial with integer coefficients and if is a zero of P(x) ( P( ) = 0 ), then p is a factor of the constant term of P(x) and q is a factor of the leading coefficient of P(x) .
</span><span>A. x – 6
</span><span>60(6)^4 + 86(6)^3 – 46(6)^2 – 43(6) + 8 = 94430
</span><span>
B. 5x – 8
</span>60(8/5)^4 + 86(8/5)^3 – 46(8/5)^2 – 43(8/5) + 8 = 566.912<span>
C. 6x – 1
</span>60(1/6)^4 + 86(1/6)^3 – 46(1/6)^2 – 43(1/6) + 8 = 0 -------> ANSWER
<span>
D. 8x + 5
</span>60(-5/8)^4 + 86(-5/8)^3 – 46(-5/8)^2 – 43(-5/8) + 8 = 5.07
It should be B because you have to have 2 angles to know for sure.
Answer:
First look at the number of bricks alone.
Going from 50 bricks to 60 bricks is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 60/50
Next look at the time alone.
Going from 30 minutes to 20 minutes is more work, thus it will require more people. The number of people would be the ratio of the 2. Since the number must be larger, you know the numerator must be the larger of the 2 numbers, so you get 30/20
Now you can just multiply everything.
= 5*60/50*30/20
= 5*6/5*3/2
= 90\10
= 9.
11/3 = 3.67
3.67 divided by 4 = 0.92
So, yes. You can have 4 bags with each one having 0.92 pound of trail mix.
Answer:
11.70% probability someone will spend no more than 30 minutes reading online national news reports.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability someone will spend no more than 30 minutes reading online national news reports?
This is at most 30 minutes, so 30 or less minutes. This is the pvalue of Z when X = 30.
So
has a pvalue of 0.1170.
So there is a 11.70% probability someone will spend no more than 30 minutes reading online national news reports.
