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Travka [436]
2 years ago
11

The areas of the squares adjacent to two sides of a right triangle are 29.2529.2529, point, 25 units^2 2 squared and 131313 unit

s^2 2 squared. Find the length, xxx, of the third side of the triangle.
Mathematics
2 answers:
Morgarella [4.7K]2 years ago
6 0

Answer:

It is 6.5 units

bonufazy [111]2 years ago
3 0

Answer:

6.5 units

Step-by-step explanation:

We are given that

Two adjacent sides of right triangle

Suppose a,b and c are sides of right triangle.

a^2=29.25squared units

b^2=13square units.

Length of third side,c=x units

We have to find the length of third side of the triangle.

x^2=a^2+b^2

By using Pythagoras theorem

(Hypotenuse)^2=(Perpendicular\;side)^2+(Base)^2

x^2=29.25+13

x=\sqrt{29.25+13}

x=6.5units

Hence, the length x of the third side of the triangle=6.5 units

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What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768
Pani-rosa [81]

Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

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Decimal form = 0.8

Fraction form = 4/5

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Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

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