<span>A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is the train’s original speed?
***
let x=original speed
x+5=increased speed
travel time=distance/speed
..
lcd:x(x+5)
150(x+5)-150x=x(x+5)
150x+750-150x=x^2+5x
x^2+5x-750=0
(x-25)(x+30)=0
x=25
What is the train’s original speed? 25 mph</span>
Answer:
its not showing up
Step-by-step explanation:
The expression represents the total amount of money Mike earned for both weeks is 2.05x dollars
<em><u>Solution:</u></em>
Given that, Mike earned x dollars the first week of his new job
He earned 5% more the second week than the first week
To find: Total amount earned in both weeks
From given,
Amount earned in first week = "x" dollars
Amount earned in second week = 5 % more than first week
Therefore,
Amount earned in second week = x + 5 % of x

Thus amount earned in second week = 1.05x dollars
<em><u>The total amount earned in both weeks:</u></em>
Total amount = Amount earned in first week + Amount earned in second week

Thus the expression represents the total amount of money Mike earned for both weeks is 2.05x dollars
Answer:
1.8
Step-by-step explanation:
Answer:
The probability is 0.2650
Step-by-step explanation:
Let's start assuming that men and women come in at the same rate.
Let's define the following random variables :
X : ''Number of people that enter a drugstore''
M : ''Number of men that enter a drugstore''
W : ''Number of women that enter a drugstore''
The number of people will be the number of men plus the number of women
⇒
X = M + W
We are also assuming that M and W are independent random variables.
X ~ Po (10)
M ~ Po (λ1)
W ~ Po (λ2)
λ1 = λ2 because we assumed that men and women come in at the same rate.
λ1 = λ2 = λ
λ1 + λ2 = λ + λ ⇒ 2λ = 10 ⇒ λ = 5
M ~ Po (5)
W ~ Po (5)
Because X is the sum of two independent Poisson random variables.
We are looking for :

Because we assume independence.

because is a Poisson random variable with λ = 5


