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2 years ago

Why do clouds tend to form around 3:00 pm and 6:00 am

1 answer:

4 0

During daytime, the sun heats the land and warms the air that rises. That lowers the pressure, causing a gradient force to bring air from the colder sea. The wind is then onshore. Small cumulus clouds form over the land, often following the coastline very closely

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Christopher is analyzing a circle, y2 + x2 = 121, and a linear function g(x). Will they intersect?

serg [7]

The complete question and the picture in the attached figure

we have that
y^2 + x^2 = 121
is a circle with center at (0,0) and radius r=11 units
and
g(x)
points (-1,14) (0,12) (1,10)

using a graph tool
see the attached figure

the answer is
A. Yes, at the positive x coordinates.

7 0

2 years ago

Mike is making a cross-country trip, It is 2,240 miles to his destination. He will return home using the same route. His car get

antoniya [11.8K]

D) 160 gallons because you get the total miles and divide it by mpg

5 0

2 years ago

Read 2 more answers

Mike earns $6.50 per hour plus 4% of his sales enter an equation for mikes total earnings, e, when he works x hours and has a to

Cerrena [4.2K]

First identify what each variable means. since X is the amount of hours he works, and he makes $6.50 an hour, you know you need to multiply those two numbers together creating the 6.50x. You also know Y is his total sales, and he earns 4% of Y. To find 4% of Y you need to turn the percent into a decimal, and to do this you move the decimal two spaces to the left. Since 4 is a whole number, the decimal is after the 4 so you get .04 as your decimal. Then youd multiply .04 by Y getting .04y. Lastly you add 6.50x + .04y to get E, mikes total earnings. So your final equation is

6.50x + .04y = e

Hope this all makes sense

3 0

2 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

2 years ago

One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north

tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, $\bar x$ = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

$t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}$

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have $t_{\alpha /2}$ = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0

2 years ago