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Arlecino [84]
2 years ago
15

Identify the examples of diffusion in the list below. Check all that apply.

Chemistry
2 answers:
Fynjy0 [20]2 years ago
4 0

Answer;

  • A teacher takes the cap off a permanent marker. A few minutes later, students at the back of the classroom complain about the odor of the marker.
  • A cooking school student burns a piece of toast. Soon, the entire kitchen smells like burnt toast.
  • Toxic fumes produced by a chemical factory are detected in the air in a town several miles away.
<h3><u>Explanation;</u></h3>
  • Diffusion is a type of passive transport that involves the movement of particles from a region of high concentration to a region of low concentration.
  • <em><u>Diffusion takes place in liquids and gases, since their particles can move randomly from one region to another.</u></em>
  • <em><u>Therefore, diffusion results from the random movement of particles in which the net movement is down the concentration gradient  that is, from a region of high concentration to a region of low concentration.</u></em>
drek231 [11]2 years ago
4 0
The first, second, and fourth are the answer just did the question
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A 8.5-liter sample of a gas at 2.0 atm and 300.0 K has 1.2 moles of the gas. If 0.65 mole of the gas is added to the sample at t
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Did you take the test? what was the answer Im stuck on this one too

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2 years ago
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How long will it take 10.0 mL of Ne gas to effuse through a porous barrier if it has been observed that 125 minutes are required
cupoosta [38]

Answer:

88.8 minutes

Explanation:

Graham's law of diffusion relates rate of difusion by the following formula

Rate1 / rate 2 = √( Mass of argon / Mass of Neon)

Where rate = volume divided by time

Rate 1 = 10 ml / t1

Rate 2 = 10 ml / t2

Rate 1/ rate 2 = 10 ml / t1 ÷ 10 ml/ t2 = t2/ t1

t2/t1 = √(Mass of argon / mass of Neon) = √( 39.984/20.179)

125 / t1 = 1.4026

t1 = 125 / 1.4026 = 88.8 minutes

7 0
2 years ago
An iron atom has a mass of ×9.2710−23g and a cooking pot has a mass of 0.500kg
morpeh [17]

The number of iron atoms in a cooking pot that has a mass of 0.500 kg can be solve by dividing it by the mass of the iron atom.

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6 0
2 years ago
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6.
RUDIKE [14]

Answer:

THE CURRENT REQUIRED TO PRODUCE 193000 C OF ELECTRICITY IS 35.74 A.

Explanation:

Equation:

Al3+ + 3e- -------> Al

3 F of electricity is required to produce 1 mole of Al

3 F of electricity = 27 g of Al

If 18 g of aluminium was used, the quantity of electricity to be used up will be:

27 g of AL = 3 * 96500 C

18 G of Al = x C

x C = ( 3 * 96500 * 18 / 27)

x C = 193 000 C

For 18 g of Al to be produced, 193000 C of electricity is required.

To calculate the current required to produce 193 000 C quantity of electricity, we use:

Q = I t

Quantity of electricity = Current * time

193 00 = I * 1.50 * 60 * 60 seconds

I = 193 000 / 1.50 * 60 *60

I = 193 000 / 5400

I = 35.74 A

The cuurent required to produce 193,000 C of electricity by 18 g of aluminium is 35.74 A

3 0
2 years ago
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a_sh-v [17]

D

Avogadro's number allows us to measure the amount of atoms or molecules in one mole of a substance.

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