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jok3333 [9.3K]
2 years ago
7

The Venn Diagram shows the number of bike and skate club members who bike (circle on the left) or skate (circle on the right). C

ompute P (S | B) and write your answer as a decimal. P (S | B) = a0 ways.
Mathematics
2 answers:
Lana71 [14]2 years ago
6 0
If i think you are doing this by the "computer way" your answer would be 0.2 ways
Mnenie [13.5K]2 years ago
6 0

Answer:

Step-by-step explanation:

The sample space, is the set of all children involved. Thus,

                  n(Samples space)=n(S)=6+15+4=25.

The letters S and C represent the sets "Swam" and "built castles", clearly.

Let

E_1, E_2, E_3, E_4, E_5,E_6

be the following events, with the following number of sets:

E_1: S.        n(E_1)= number of all those who swam =21.

E_2: S or C, but not both.        n()=6+4=10, because there are 6 of those who swam but not built castles, and 4 of those who built castles but not swam.

: C.         n(E_3)=15+4=19.

: S ∪ C.         n(E_4)=6+15+4=25.

: C, but not S.         n(E_5)=4, as there are only 4 who built castles but not swam.

: S ∩ C.         n(E_6)15, as they are 15 who built castles and swam.

The formula for the probability P(E)  of an event E is P(E)=n(E)/n(S).

Thus, the probabilities are as follows:

P(E_1)=n(E_1)/n(S)=21/25=0.84

P(E_2)=n(E_2)/n(S)=10/25=0.4

P(E_3)=n(E_3)/n(S)=19/25=0.76

P(E_4)=n(E_4)/n(S)=25/25=1.0

P(E_5)=n(E_5)/n(S)=4/25=0.16

P(E_6)=n(E_6)/n(S)=15/25=0.6

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Line 1 produces twice as many bags as line 2. Let x be the number of bags produced by line 2.

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Probability that the bag has been produced by line 1 can be written as:

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<u>P(A∩B) = P(A|B)*P(B)</u>

The chosen defective bag can be either from line 1 or from line 2. So, the probability that the chosen bag is defective is:

P(Bag is Defective) = P(Defective and from Line 1) + P(Defective and from Line 2)

                                = P(D∩Line 1) + P(D∩Line 2)

                                = P(Defective|Line 1)*P(Line 1) + P(Defective|Line 2)*P(Line 2)

                                = (0.01)*(2/3) + (0.03)(1/3)

P(Bag is Defective) = 0.0167

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21 years

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Use the equation 2000(1.02)^{x} = 3000 where x is the number of years passed.

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Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
lilavasa [31]

Answer:

The teacher should use the median for Amo and the mean for Javier.

Complete question;

Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on the median or the mean

Test

Number

Amo’s Scores

Javier’s Scores

1

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68

2

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97

3

89

65

4

55

92

5

90

65

What measure of center should Mr. Malloy use for Amo and for Javier for the best possible grade?

The teacher should use the mean for both Amo and Javier.

The teacher should use the median for both Amo and Javier.

The teacher should use the median for Amo and the mean for Javier.

The teacher should use the mean for Amo and the median for Javier.

Attached is the image of their scores

Step-by-step explanation:

Amo's Score in Ascending Order: 55,89,90,92,97

Javier's Score in Ascending Order: 65,65,68,92,97

For Amo;

Mean = (55+89+90+92+97)/5 = 84.6

Median = 90

For Javier;

Mean = (65+65+68+92+97)/5 = 77.4

Median = 68

Therefore,

Median is higher for Amo and mean is higher for Javier

So, The teacher should use the median for Amo and the mean for Javier.

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