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2 years ago

A piece of string is 325 centimeters long. You need the string to be 114 meters long. How many centimeters should you cut off?

1 answer:

5 0

There are 100 centimeters in 1 meter.1 and 1/4 meters can also be written as 1.25, since 1/4 = 0.25.To find the answer, convert 1.25 meters to centimeters.
1 meter = 100 centimeters1.25 meters = x centimeters1.25 is 125% of 1. In other words, there is a 25% increase.
Now apply this increase to the centimeters side.125% = 1.251.25 • 100 = 125
So 1.25 meters (1 and 1/4 meters) equals 125 centimeters.
The string is 325 centimeters.In order for the string to be 125 centimeters, you need to cut some off.To find how much you need to cut off, subtract 125 from 325.325 - 125 = 200
Answer: In order for your string to be 1 and 1/4 meters, you must cut 200 centimeters off the original 325 centimeter long string.

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a rectangular flower garden has area of 32 square feet. if the width of the garden is 4 feet less than the length, what is the p

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Let length be x feet
length= x
width=x-4
area = 32
length * width=32
x(x-4)=32
x^2 - 4 x -32=0
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x=8 feet
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Answer:

D. H0: p ≤0.36 H1: p>0.36

$$$(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155$

$Z_p=-0.25516$

D. Reject H0. There is sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population proportion.

$$$Sample proportion: $\bar P=0.47\\Sample size n=100$\\Significance level \alpha=0.10$\\(Left tail test) Z_{1-\alpha}=Z_{0.90}=-1.28155$\\(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155$\\(Two-tailed test) $Z_{1-\alpha/2}=Z_{0.95}=-1.64485$ and $ Z_{\alpha/2}=Z_{0.05}=1.64485\\\\$

The appropriate hypothesis system for this situation is:

$H_0:\pi_0=0.35\\H_a:\pi_0 > 0.35\\\\$Proportion in the null hypothesis is:\\\pi_0=0.35\\\\$

$$$The test statistic is $Z=\frac{(\bar P-\pi_0)\sqrt{n}}{\sqrt{\pi_0(1-\pi_0)}}\\$The calculated statistic is Z_c=\frac{(0.47-0.35)\sqrt{100}}{\sqrt{0.35(1-0.35)}}=-0.25516\\p-value = P(Z \geq Z_c)=0.01620\\\\$

Since, the calculated statistic $Z_c$ is greater than critical $Z_{\alpha}$ , the null hypothesis should be rejected. There is enough statistical evidence to state that the proportion of admissions officers who visit an applying students' social networking page has increased in the past year.

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