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REY [17]
2 years ago
14

Roberto's toy car travels at 40 centimeters per second (cm/sec) at high speed and 15 cm/sec at low speed. If the car travels for

15 seconds at high speed and then 30 seconds at low speed, what distance would the car have traveled?
Mathematics
2 answers:
klio [65]2 years ago
7 0

Answer:

Step-by-step explanation:

15 seconds at high speed

1 sec = 40 cm

15 sec = 40 x 15

15 sec = 600 cm

30 seconds at low speed

1 sec = 15 cm

30 sec = 15 x 30

30 sec = 450 cm

Total distance = 600 + 450 = <u>1050 cm</u>

kobusy [5.1K]2 years ago
6 0
15 seconds at high speed
1 sec = 40 cm
15 sec = 40 x 15
15 sec = 600 cm

30 seconds at low speed
1 sec = 15 cm
30 sec = 15 x 30 
30 sec = 450 cm

Total distance = 600 + 450 = 1050 cm
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If x=0 then they have same value

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4th
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2 years ago
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Okay,
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So,
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To make sure add.
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3 0
2 years ago
The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as
Rzqust [24]

Answer:

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The best answer choice appears to be 109.9 feet.

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gulaghasi [49]
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Answer:

D

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We calculate the z-score for each

Mathematically;

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P(-1<x<1)

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