Ask question

Ask question

All categories

1 year ago

15

The points plotted below are on the graph of a polynomial. In what range of x-values must the polynomial have a root?

1 answer:

joja [24]1 year ago

6 0

Actually, I think the question should be, "In what range(s) of x-values must there be a root of the POLYNOMIAL?" Unless you are working with some real strange maths, polynomials are smooth and continuous. If you drew a smooth and continuous line through the points in the graph, where would the line have to cross the x-axis?

You might be interested in

Find the P-value in a test of the claim that the mean IQ score of acupuncturists is equal to 100, given that the test statisti

klemol [59]

Answer:

P-value = 0.0455

Step-by-step explanation:

In this question, we are concerned with calculating the P- value in a test.

Mathematically we know that;

P-value = 2 * P(Z > |z|)

Please check attachment for complete solution and by step explanation

7 0

1 year ago

Sum of positive roots of the equation (x2 - 12x + 35) (x2 + 10x + 24) = 504 is

Digiron [165]

Answer:

(3)11

Step-by-step explanation:

We are given that

$(x^2-12x+35)(x^2+10x+24)=504$

We have to find the sum of positive roots of the equation.

$x^2(x^2+10x+24)-12x(x^2+10x+24)+35(x^2+10x+24)=504$

$x^4+10x^3+24x^2-12x^3-120x^2-288x+35x^2+350x+840=504$

$x^4-2x^3-61x^2+62x+840-504=0$

$x^4-2x^3-61x^2+62x+336=0$

Factor of 336

2,3,4,6,8,7,

Let x=2

$2^4-2^4-61(2^2)+62(2)+336\neq0$

x=2 is not the root of equation

x=-2

$(-2)^4-2(-2)^3-61(-2)^2+62(-2)+336=0$

Hence x=-2 is the root of equation.

x+2 is a factor of equation.

x=3

$3^4-2(3^3)-61(3^2)+62(3)+336=0$

Therefore, x=3 is the root of equation.

$(x+2)(x-3)(x^2-x-56)=0$

$(x+2)(x-3)(x^2-8x+7x-56)=0$

$(x+2)(x-3)(x(x-8)+7(x-8))=0$

$(x+2)(x-3)(x-8)(x+7)=0$

$x-8=0\implies x=8$

$x+7=0\implies x=-7$

Positive roots are 3 and 8

Sum of positive roots=3+8=11

Option (3) is true.

4 0

1 year ago

On a coordinate plane, parallelogram P Q R S is shown. Point P is at (negative 2, 5), point Q is at (2, 1), point R is at (1, ne

Oksanka [162]

Answer:

The perimeter is $(8\sqrt{2}+2\sqrt{10})\ units$

Step-by-step explanation:

we know that

A parallelogram is a quadrilateral where both pairs of opposite sides are parallel and equal

so

In this problem

PS=QR ----> equation A

SR=PQ ----> equation B

The perimeter of parallelogram PQRS is

P=PQ+QR+SR+PS ----> equation C

substitute equation A and equation B in equation C

$P=2SR+2QR$

we have

$QR=\sqrt{10}\ units$

$SR=4\sqrt{2}\ units$

substitute in the formula of perimeter

$P=2(4\sqrt{2})+2(\sqrt{10})$

$P=(8\sqrt{2}+2\sqrt{10})\ units$

7 0

2 years ago

Read 2 more answers

At noon (12:00), Annette rented a bicycle to travel around Stanley Park. She returned the bicycle at 4:00 pm (16:00) the same da

Doss [256]

Answer:

a. average speed is 12km/hr

b. $5.50 dollars per hour

c. $0.46 per km

Step-by-step explanation:

a. 48km/4hrs = 12km/hr

b. $22/4hrs = $5.50/hr

c. $22/48km = $0.45833/km rounded to $0.46/km

6 0

2 years ago

will crown brainliest Stephanie puts 30 cubes in a box. The cubes are 1/2 inch on each side. The box holds two layers with 15 cu

KiRa [710]

15 cubic inches is the answer hope this helps and please give me brainiest

5 0

1 year ago

Read 2 more answers