The points plotted below are on the graph of a polynomial. In what range of x-values must the polynomial have a root?
1 answer:
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A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
</span>
For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
</span>
For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.
Answer:
For First Solution:
is the solution of equation y''-y=0.
For 2nd Solution:
is the solution of equation y''-y=0.
Step-by-step explanation:
For First Solution:
In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.
First order derivative:
2nd order Derivative:
Put Them in equation y''-y=0
e^t-e^t=0
0=0
Hence is the solution of equation y''-y=0.
For 2nd Solution:
In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.
First order derivative:
2nd order Derivative:
Put Them in equation y''-y=0
cosht-cosht=0
0=0
Hence is the solution of equation y''-y=0.