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Tomtit [17]
2 years ago
9

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

ion of bees seems to be decreasing steadily at a rate of 5% per year. If the number of bees in the population after x years is represented by f(x), which statements about the situation are true? Check all that apply. The function f(x) = 9,000(1.05)x represents the situation. The function f(x) = 9,000(0.95)x represents the situation. After 2 years, the farmer can estimate that there will be about 8,120 bees remaining. After 4 years, the farmer can estimate that there will be about 1,800 bees remaining. The domain values, in the context of the situation, are limited to whole numbers. The range values, in the context of the situation, are limited to whole numbers.
Mathematics
2 answers:
nataly862011 [7]2 years ago
7 0
These statements will be true:
  The function f(x) = 9000(0.95)ˣ represents the situation.
  After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
  The range values, in the context of the situation, are limited to whole numbers.
natima [27]2 years ago
5 0
He is correct its 2,3,and 6
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Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
2 years ago
Rodolpho uses a prepaid gas card to spend $35 each week for gas. After the first week, he has $140 left on the card. After every
noname [10]

I got this T_T y=175-35t

But maybe its y= -35t + 175 since its negative :)

4 0
2 years ago
Most graduate business schools require applicants to take the gmat. scores on this test are approximately normally distributed w
Harman [31]
We are looking for the probability :
P(X > n)=0.05
Transform the law to standard normal like this:
P(\dfrac{X-545}{100}> \dfrac{n-545}{100})=0.05
The above formula is equivalent to this one:
P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
From normal law table, we read the value of \dfrac{X-545}{100}.
\dfrac{X-545}{100}=1.7
Solving the above equation for the score n:
X-545=170
X=715, it is the score we are looking for. 
5 0
2 years ago
Jabari owns 100 shares of Stock A and 45 shares of Stock B. For the past month, his stocks have been fluctuating inversely each
aniked [119]
This is how we solved and make the equation.
Stock A = 100
Stock B = 45

For the past months, his stocks inversely decreased.
Stock A = m cents / share
Stock B = n cents * share

So the equation is
= 100 (0.01m) + 45 (0.01n)
<span>= m + 0.45n</span>
6 0
2 years ago
Help me with this question!!!
qwelly [4]

Step-by-step explanation:

×=100

1. Divded 35 by 14 and u get 0.4

2

Divided 40 by 0.4 and u get 100

6 0
2 years ago
Read 2 more answers
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