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2 years ago

What is the next letter? Y B W D U F

1 answer:

5 0

The correct answer is S. The sequence is each alternate letter, changing from one end of the alphabet to the other.

Z Y X W V U T S R Q P L M N O K J I H G F E D C B A
Since we started at the end of the alphabet and then went back to the beginning, there are two letters in the middle that aren't part of the pattern. We only need to worry about which letter is next at the end of the alphabet, though, and the next highlighted letter after U is S.

Hope this helps!

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2 years ago

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Which will result in a perfect square trinomial?

Margaret [11]

(3x-5)(3x-5)
Because it's (3x-5)²=9x²-30x+25

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2 years ago

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Which of the following are dimensionally consistent? (Choose all that apply.)(a) a=v / t+xv2 / 2(b) x=3vt(c) xa2=x2v / t4(d) x=v

Bumek [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

is dimensionally consistent

is not dimensionally consistent

is dimensionally consistent

is not dimensionally consistent

is dimensionally consistent

is not dimensionally consistent

Step-by-step explanation:

From the question we are told that

The equation are

$A) \ \ a^3 = \frac{x^2 v}{t^5}$

$B) \ \ x = t$

$C \ \ \ v = \frac{x^2}{at^3}$

$D \ \ \ xa^2 = \frac{x^2v}{t^4}$

$E \ \ \ x = vt+ \frac{vt^2}{2}$

$F \ \ \ x = 3vt$

$G \ \ \ v = 5at$

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$

Generally in dimension

x - length is represented as L

t - time is represented as T

m = mass is represented as M

Considering A

$a^3 = (\frac{L}{T^2} )^3 = L^3\cdot T^{-6}$

and $\frac{x^2v}{t^5 } = \frac{L^2 L T^{-1}}{T^5} = L^3 \cdot T^{-6}$

Hence

$a^3 = \frac{x^2 v}{t^5}$ is dimensionally consistent

Considering B

$x = L$

and

$t = T$

Hence

$x = t$ is not dimensionally consistent

Considering C

$v = LT^{-1}$

and

$\frac{x^2 }{at^3} = \frac{L^2}{LT^{-2} T^{3}} = LT^{-1}$

Hence

$v = \frac{x^2}{at^3}$ is dimensionally consistent

Considering D

$xa^2 = L(LT^{-2})^2 = L^3T^{-4}$

and

$\frac{x^2v}{t^4} = \frac{L^2(LT^{-1})}{ T^5} = L^3 T^{-5}$

Hence

$xa^2 = \frac{x^2v}{t^4}$ is not dimensionally consistent

Considering E

$x = L$

;

$vt = LT^{-1} T = L$

and

$\frac{vt^2}{2} = LT^{-1}T^{2} = LT$

Hence

$E \ \ \ x = vt+ \frac{vt^2}{2}$ is not dimensionally consistent

Considering F

$x = L$

and

$3vt = LT^{-1}T = L$ Note in dimensional analysis numbers are

not considered

Hence

$F \ \ \ x = 3vt$ is dimensionally consistent

Considering G

$v = LT^{-1}$

and

$at = LT^{-2}T = LT^{-1}$

Hence

$G \ \ \ v = 5at$ is dimensionally consistent

Considering H

$a = LT^{-2}$

$\frac{v}{t} = \frac{LT^{-1}}{T} = LT^{-2}$

and

$\frac{xv^2}{2} = L(LT^{-1})^2 = L^3T^{-2}$

Hence

$H \ \ \ a = \frac{v}{t} + \frac{xv^2}{2}$ is not dimensionally consistent

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2 years ago

At an archeological site, the remains of two ancient step pyramids are congruent. If ABCD~=EFGH, find AD

worty [1.4K]

Answer: 300ft

Step-by-step explanation:

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2 years ago

Look at picture, answer quick please

Tpy6a [65]

Step-by-step explanation:

1. C = the graphing is slowly increasing, then he walks across the top so it is flat

2. D = it started out slow and gradually got higher, which is what the story said

3. H = he had to stop walking, and there is a part of no movement in the graph H

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2 years ago