I believe the answer to the multiple choice is c I’m not to sure
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Answer:
What are the 3 elements in all triglycerides?
Carbon, hydrogen and oxygen
Explanation:
Answer:Naturally occurring,inorganic substance.
Explanation:
Answer:
B. 0.50
Explanation:
The estimated frequency of allele A in the gene pool is 0.50. Allele A is a variant form of gene which has different forms located at same position. Allele frequency determines common presence of genetic locus of an allele in the population. It is calculated by dividing the number of common allele that appears in the population by total number of copies of genes.