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Andrews [41]
2 years ago
13

100 POINTS!!!!Questions/Results Heat energy, Q, is calculated by multiplying the mass of the object in grams, m, by the change o

f temperature, mΔT, and the specific heat, Cp, of the material. Q = mΔT(Cp) Calculate the heat lost from the bread at each interval. Assume that the specific heat capacity of bread is 2.73 J/g °C. Calculate the heat gained by the water at each interval. Assume that the specific heat capacity of water is 4.19 J/g °C. Based upon the results in Questions 1 and 2, formulate a hypothesis regarding the transfer of heat between the bread and the water. Identify at least one improvement that could be made to this experiment. Justify your response in two or more complete sentences. What other household items could be used with your calorimeter? Do you expect to get a different result? Justify your response in two or more complete sentences. Submission Requirements Title of Lab: Data Tables: Questions/Results:
Chemistry
2 answers:
Sav [38]2 years ago
7 0

Q = mΔT(Cp)

where Q = heat energy in J (joules),

m = mass in g, ΔT = change in temper. (°C),

Cp = heat capacity in J/(g°C)


Water has a higher heat capacity, meaning that once heat energy is absorbed, it holds that heat longer than bread. Also though, a higher heat capacity of water means that it takes more energy to heat it up

zepelin [54]2 years ago
5 0
Q = mΔT(Cp)
where Q = heat energy in J (joules),
m = mass in g, ΔT = change in temper. (°C),
Cp = heat capacity in J/(g°C)

Water has a higher heat capacity, meaning that once heat energy is absorbed, it holds that heat longer than bread. Also though, a higher heat capacity of water means that it takes more energy to heat it up.

I don't see any specific data listed for this lab??
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nataly862011 [7]

The arrow shows that the bond between the chlorine atom and the fluorine atom is nonpolar. The electrons in the bond are pulled more strongly by the fluorine atom, and the chlorine atom is slightly positive.

Explanation:

  • The bond between Chlorine and fluorine is nonpolar bonding because both of them are sharing an equal number of electrons in the bond. H2, F2, and CL2 are common examples of this.
  • Chlorine and fluorine are electronegative molecules but Fluorine is above chlorine in the periodic table. Since fluorine is above Chlorine, fluorine has slightly highest electronegative nature compare to fluorine. This is the reason why Fluorine molecules are attracting electrons more than chlorine atoms. This making chlorine atoms slightly positive in Cl and F bonding.

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Precipitation will increase in areas where there is A) less transpiration and less run-off. B) lower temperatures and more evapo
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2 years ago
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nordsb [41]

Answer:

The answer to your question is  molality = 0.61

Explanation:

Freezing point is the temperature at which a liquid turns into a solid if a solute is added to a solution, the freezing point changes.

Data

Kf = 1.86 °C/m

molality = ?

ΔTc = 1.13°C

Formula

ΔTc = kcm

Solve for m

m = ΔTc/kc

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4 0
2 years ago
A sample of 508.4 grams of copper completely reacted with oxygen to form 572.4 grams of a copper oxide product. how many grams o
Svet_ta [14]

According to law of conservation of mass, mass can neither be destroyed nor created in a chemical reaction. Thus, sum of masses of reactants must be equal to sum of masses of products in a reaction.

The chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, sum of masses of Cu and oxygen gas should be equal to CuO formed.

2m_{Cu}+m_{O_{2}}=2m_{CuO}

Thus, mass of oxygen will be:

m_{O_{2}}=2(572.4-508.4)g=128 g

This can be further proved as follows:

The balanced chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, 2 moles of Cu completely reacts with 1 mole of O_{2} to give 2 moles of CuO.

Thus, 1 mole of Cu reacts with 0.5 moles of O_{2} .

The mass of Cu is 508.4 and molar mass is 63.546 g/mol, number of moles can be calculated as follows:

n=\frac{m}{M}=\frac{508.4 g}{63.546 g/mol}=8 mol

Thus, number of moles of  O_{2} reacting will be:

n_{O_{2}}=8\times 0.5 mol=4 mol

Molar mass of oxygen molecule is 32 g/mol thus, mass can be calculated as follows:

m=n×M=4 mol×32 g/mol=128 g/mol

This satisfies the law of conservation of mass.


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Answer:

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