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Nat2105 [25]
1 year ago
12

An afterschool program offers tutoring for different subjects during the last month, a teacher recorded the number of students w

ho participated in tutoring in each subject as shown in the table below. explain how the teachers could use this data to predict how many of the next 100 students will participate in math tutoring.
(chart)
Subject - Number of Students
Math 40
Science 55
English 47
History 58
Mathematics
1 answer:
Tasya [4]1 year ago
6 0
I’m not exactly sure, but I think you have to find the percentage of the people in the math tutoring compared to the total. You can do this by finding the total number of people, which would be 200, and then dividing 40 by 200, to get 20%, so 20% of the total students participated in the math tutoring. So, using this logic, 20% of 100 is 20, so 20 students would go to math tutoring if there was a total of 100 students
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Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
2 years ago
Assume there are 365 days in a year.
MissTica

Answer:

1) The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.

Step-by-step explanation:

Given : Assume there are 365 days in a year.

To find : 1) What is the probability that ten students in a class have different birthdays?

2) What is the probability that among ten students in a class, at least two of them share a birthday?

Solution :

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

Total outcome = 365

1) Probability that ten students in a class have different birthdays is

The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...

\frac{364}{365}\times \frac{363}{365} \times \frac{362}{365} \times \frac{361}{365}\times\frac{360}{365} \times \frac{359}{365} \times \frac{358}{365} \times \frac{357}{365} \times\frac{356}{365}=0.883

The probability that ten students in a class have different birthdays is 0.883.

2) The probability that among ten students in a class, at least two of them share a birthday

P(2 born on same day) = 1- P( 2 not born on same day)

\text{P(2 born on same day) }=1-[\frac{365}{365}\times \frac{364}{365}]

\text{P(2 born on same day) }=1-[\frac{364}{365}]

\text{P(2 born on same day) }=0.002

The probability that among ten students in a class, at least two of them share a birthday is 0.002.

6 0
2 years ago
Greta is taking a road trip from Cincinnati to San Francisco. On the first day, she drove 650 miles in 10 hours. On the second d
abruzzese [7]

Given:

On the first day, she drove 650 miles in 10 hours.

On the second day, she got a later start and drove 540 miles in 8 hours.

To find:

Difference between average speed of second day and first day.

Solution:

We know that,

Speed=\dfrac{Distance}{Time}

On the first day, she drove 650 miles in 10 hours.  So, the average speed is

Speed=\dfrac{650}{10}

Speed=65

So, the average speed on first day is 65 miles per hour.

On the second day, she got a later start and drove 540 miles in 8 hours.

Speed=\dfrac{540}{8}

Speed=67.5

So, the average speed on second day is 67.5 miles per hour.

Difference between average speed is

67.5-65=2.5

Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.

3 0
1 year ago
Drag the tiles to the boxes to form correct pairs. In the diagram, transversal t cuts across the parallel lines a and b. Match t
yarga [219]
Where are the type of answers for this question
7 0
1 year ago
Read 2 more answers
If cos(t) = 2/7 and t is in the 4th quadrant, find sin(t).
Yuliya22 [10]
We can use the Pythagorean Trigonometric Identity which says:
sin^2(t)+cos^2(t)=1

Since we need to find sin(t), we have to solve for it:
sin(t)= \sqrt{1-cos^2(t)}

Let's plug in the given cos(t) value:
sin(t) = \sqrt{1-cos^2( \frac{2}{7})}

And solve sin(t):
sin(t) = \sqrt{1- \frac{4}{49} } = \frac{x}{y} \sqrt{ \frac{49}{49}- \frac{4}{49} }

Simplify further:
sin(t) = \sqrt{ \frac{45}{49} } = \frac{ \sqrt{45} }{7} = \frac{ \sqrt{9*5} }{7}

And it all simplifies down to:
sin(t) = \frac{3 \sqrt{5} }{7}

Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is: 
sin(t) = - \frac{ 3\sqrt{5} }{7}

Hope this helps!
7 0
2 years ago
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