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2 years ago

Mark jogged 0.6 mile. Caroline jogged 0.49 mile write an inequality to compare the distances they jogged

2 answers:

8 0

Hi there,

The answer is going to be 0.11 miles. Here’s how....

We are going to subtract Caroline’s miles, and Marks miles. In this case we have 0.6 and 0.49

0.6 mi - 0.49 mi = 0.11 mi
0.11 miles is the difference

lakkis [162]2 years ago

4 0

Marks traveled further than Caroline. Therefore,
0.6>0.49

This is because 0.6 is actually 0.60. If it was , it would be 0.06.

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Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

shepuryov [24]

The probability that both the chosen students are sophomores is 6/20 or 3/10 simplified.
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2 years ago

Read 2 more answers

I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,

lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So , The number of customer after n hours = initial number × $(1+\dfrac{\textrm rate}{100})^{n}$

or, The number of customer after 8 hours = 8 × $(1+\dfrac{\textrm 20}{100})^{8}$

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34 answer

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2 years ago

You put $350 per month in an investment plan that pays an APR of 3.5% compounded monthly. How much will you have after

melamori03 [73]

Answer: B.

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N = 216 (12 x 18 years)

I% = 3.5

PV = 0

PMT = - $350

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C / Y = 12

PMT: END

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2 years ago

11. Imagine that the stone is part of an arch, and that there is an isosceles triangle JEF formed by extending sides GE and HF d

Anna11 [10]

Answer:

one for each angle measure) Line GJ is transversal, and since the bases ... I cannot add the measurement to my drawing by they are both 84 degrees. i hope i helped??

Step-by-step explanation:

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2 years ago

In ΔXYZ, x = 71 cm, y = 91 cm and z=71 cm. Find the area of ΔXYZ to the nearest square centimeter.

anyanavicka [17]

since its an isoscelies trangle, they probably wanted you to do base times height

make a 71-91/2-x x triangle

where x is the height of the triangle to the base 91 and 71 is the hypothenuse

and then do bh/2

use heron's formula

s= 71+91/2

area= $\sqrt{(71+91/2)(71+91/2-71)(71+91/2-71)(71+91/2-91)}$

have fun solving that

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2 years ago