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eduard
1 year ago
8

A recent study of the hourly wages of maintenance crew members for major airlines showed that the mean hourly salary was $20.50,

with a standard deviation of $3.50. assume the distribution of hourly wages follows the normal probability distribution. we select a crew member at random. what is the probability the crew member earns
Mathematics
1 answer:
RSB [31]1 year ago
8 0
You ended without giving the values, so we can't get the exact answer. However, I can tell you steps.

First, you need to find the z-score. Then, look up the z-score on a normal distribution table and you will get the percent.

Let's call your value X. Just plug X into the equation below and you will have your z-score.

(x - 20.5) / 3.5 = z

Now, look up the z-score and you will have your probability.<span />
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A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

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maksim [4K]

Answer:

ABCD is a parallelogram

Step-by-step explanation:

Given: AD ≅ BC and AD ∥ BC Prove: ABCD is a

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1. given 2. ∠CAD and ∠ACB are alternate interior ∠s 2.

definition of alternate interior angles 3. ∠CAD ≅ ∠ACB 3.

alternate interior angles are congruent 4. AC ≅ AC 4.

reflexive property 5. △CAD ≅ △ACB 5. SAS congruency

theorem 6. AB ≅ CD 6. ? 7. ABCD is a parallelogram 7.

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Answer:3.9

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you have to add the decimal to the exponent

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2

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