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77julia77 [94]
2 years ago
15

What is the median length, in feet, of the blades of the five models?

Mathematics
2 answers:
Mila [183]2 years ago
4 0
The median should be 5
yanalaym [24]2 years ago
4 0

Answer:

146 the median is the middle value in a odd number of order values.

1,2,3,4,5 your meadian is 3

Step-by-step explanation:


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Eileen is taking a trip to Louisiana and expects to drive 850 miles round trip. If her car gets 23 miles per gallon, and the cos
bazaltina [42]
The answer is <span>$103.

To determine </span><span> how much Eileen will spend on gasoline, first we need to calculate how many gallons she needs.
If she drives 850 miles and </span><span>her car gets 23 miles per gallon, we can use the proportion:
850 miles : x gallons = 23 miles : 1 gallon
Crossing the products:
x = 850 miles </span>× 1 gallon ÷ 23 miles
x = 36.96 gallons

Thus, Eileen needs 36.96 gallons of gas. If the cost per gallon of gas is$2.79, using the proportion:
36.96 gallons : x = 1 gallon : <span>$2.79
x = 36.96 gallons </span>× $2.79 <span>÷ 1 gallon
x = </span>$103.12 
x ≈ $<span>103</span>
4 0
2 years ago
A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil
MArishka [77]

Answer:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

X \sim N(12,0.3)  

Where \mu=12 and \sigma=0.3

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}

If we solve for the total T we got:

T= n \bar X

For this case then the expected value and variance are given by:

E(T) = n E(\bar X) =n \mu

Var(T) = n^2 Var(\bar X)= n^2 \frac{\sigma^2}{n}= n \sigma^2

And the deviation is just:

Sd(T) = \sqrt{n} \sigma

So then the distribution for the total would be also normal and given by:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

And we want this probability:

P(T\leq 72)

And we can use the z score formula given by:

z = \frac{x-\mu}{\sigma}

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

6 0
2 years ago
The daily energy requirement, E (kilojoules), for a person of mass m ( kilograms) is calculated using the rule E=9m+8100
Wewaii [24]
For this case we have the following equation:
 E = 9m + 8100
 Substituting E = 8865 we have:
 8865 = 9m + 8100
 Clearing m we have:
 9m = 8865-8100
 m = (8865-8100) / (9)
 m = (765) / (9)
 m = 85 Kg
 Answer:
 
Gavin's mass is:
 
m = 85 Kg
8 0
2 years ago
Why is sin(20) = sin(160) = -sin(200) = -sin(340)?
AveGali [126]
Because they're all the same distance from the x axis on a coordinate plane. Also, remember that in quadrant I, all trig values are positive. In Q II, only sine and cosecant are positive. In Q III, only tangent and cotangent are positive. In Q IV, only cosine and secant are positive. Think of it as <u>A</u>ll <u>S</u>tudents <u>T</u>ake <u>C</u>alculus.
6 0
2 years ago
Read 2 more answers
if the Browns plant 3/16 tomatoes, 1/4cabbage, and 2/8pepper, what fraction of their garden will be unplanted?
zysi [14]
5/16 will be unplanted
3/16+4/16+4/16=11/16
16/16-11/16=5/16
6 0
2 years ago
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