The solution to this system is (x, y) = (8, -22).
The y-values get closer together by 2 units for each 2-unit increase in x. The difference at x=2 is 6, so we expect the difference in y-values to be zero when we increase x by 6 (from 2 to 8).
You can extend each table after the same pattern.
In table 1, x-values increase by 2 and y-values decrease by 8.
In table 2, x-values increase by 2 and y-values decrease by 6.
The attachment shows the tables extended to x=10. We note that the y-values are the same (-22) for x=8 (as we predicted above). That means the solution is ...
... (x, y) = (8, -22)
Answer : Remaining two observation becomes 97 and 107.
Explanation :
Since we have given that
Mean = 100
Modal value = 98
Range = 10
As we know that ,
Range = Highest-Lowest
Let highest observation be x
Let lowest observation be y
So equation becomes x-y=10 ----equation 1
So, observation becomes
x,98,98,y
Now, we use the formula of mean i.e.
Mean = 
So, mean =
So our 2nd equation becomes
x+y=204
On using elimination method of system of linear equation on these two equation we get,
x=97
and
Hence , remaining two observation becomes 97 and 107.
Answer:
volume of trapezoidal prism = 15x^2 cubic units
Step-by-step explanation:
First, area of the trapezoidal bases.
Parallel sides measure x and 2x, for an average of 1.5x.
Height = x
Area of trapezoidal base = 1.5x*x = 1.5x^2
Volume of prism = area base * height
(length does not matter, height does)
= 1.5x^2 * 10 = 15x^2
If it takes yards and turns it into feet then it just multiplies it by 3
so if the input is 10.5 then you just multiply it by three
31.5 feet is the imput
Answer:
1. x=±4
2. t=±9
3. r=±10
4. x=±12
5. s=±5
Step-by-step explanation:
1. x^2 = 16
Taking square root on both sides
x=±4
2. t^2=81
Taking square root on both sides
t=±9
3. r^2-100=0
r=±10
4. x²-144=0
x²=144
Taking square root on both sides
x=±12
5. 2s²=50
s=±5 ..
