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CaHeK987 [17]
2 years ago
4

4.1.4 practice: modeling: leaning towers.. Geometry Apex class...Can’t figure out how to do this

Mathematics
1 answer:
gladu [14]2 years ago
6 0
Observe attached picture.

Letter a marks lean. Letter b marks height of leaned tower. Letter c marks length of side of tower.

a=7.4 feet
b=94 feet
c=?

From the picture we can see that we have right-angle triangle. We can use pythagorean theorem to solve for c.
a^{2} + b^{2} = c^{2}  \\  \\  7.4^{2} + 94^{2} = c^{2}  \\  \\  c^{2} =8890.76 \\  \\ c=94.3feet

We can use law of sines to solve for lean angle:
\frac{a}{sin \alpha } = \frac{b}{sin  \beta  }= \frac{c}{sin \gamma }
We will use part:
\frac{b}{sin \beta }= \frac{c}{sin \gamma } \\  \\ c*sin \beta=b*sin \gamma \\  \\ sin \beta= \frac{b*sin \gamma}{c}  \\  \\ sin \beta= \frac{94*sin \90}{94.3}   \\  \\  sin \beta=0.99681866 \\  \\ \beta=85.4

Tower makes angle of 85.4° with respect to ground or 4.6° with respect to vertical line.

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Answer:

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18 bags of nuts

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2 years ago
3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
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Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

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The expected value of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

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0% probability that at least 1,500 will agree to respond

6 0
2 years ago
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Answer:

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