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mixer [17]
2 years ago
10

The coordinates of triangle FGH are F(2, 4), G(5, −9) and H(−3, −4). Which statement proves that triangle FGH is a right triangl

e? (m = y2 - y1 x2 - x1 )
Mathematics
2 answers:
Alecsey [184]2 years ago
3 0
The fact that the slopes of HF and GH are negative reciprocals proves that FGH is a right triangle.

The slope of HF is given by
m = (-4-4)/(-3-2) = -8/-5 = 8/5

The slope of GH is given by
m = (-4--9)/(-3-5) = (-4+9)/(-3-5) = 5/-8 = -5/8

These are reciprocals and opposite sides.  This only occurs if the lines are perpendicular; thus they make a right angle.
ArbitrLikvidat [17]2 years ago
3 0

The slope of GH= -5/8, and the slope of FH=8/5, therefore, GH | FH

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Translate and solve: Three more than the difference of 6s and 5s is equal to the difference of 1/12 and 1/6
PilotLPTM [1.2K]

Answer:

a. (6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. s=-\frac{37}{12}

Step-by-step explanation:

You need to remember that:

1. The word "more" indicates Addition.

2. The "Difference" is the result of a Subtraction.

a. Then, knowing this information, you know that:

- "The difference of 6s and 5s" must be expressed as:

6s-5s

- Then, "Three more than the difference of 6s and 5s " is:

(6s-5s)+3

- "The difference of  \frac{1}{12} and \frac{1}{6} " can be expressed in this form:

\frac{1}{12}-\frac{1}{6}

Therefore, "Three more than the difference of 6s and 5s is equal to the difference of  \frac{1}{12} and \frac{1}{6} " is:

(6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. Solve for "s" in order to find its value:

s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}

8 0
2 years ago
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Maru [420]
A) System of inequalities

Income from babysitting: 6x
Income from tutoring: 10y

Goal for this week: at least $ 75 => 6x + 10y ≥ 75
Number of hours: maximum $20 => x + y ≤ 20

x and y have to be zero or positvie => x≥0 and y ≥ 0

Answer of part A.

6x + 10y ≥ 75
x+y ≤ 20
x ≥ 0
y ≥ 0

Part B. Graph

The solution is a region closed by 4 lines and you can find it in the file attached.

In that graph:

1) the line x + y = 20 is the upper limit
2) the line 6x + 10 y = 75 is the lower incclined line
3) y = 0 is the botton horizontal line it is the x-axis
4) x = 0 is the left vertical line, in is the y-axis

Part C.

Use, for example the point (7,10).

It is in the region of the graph limited by the above equations.

It implies:

Number of hours worked = 7 + 10 = 17 which is less than 20.

Income: 6(7) + 10(10) = 42 + 100 = 142, which is greater than 75

Of course, both are greater than 0.

In this way we proved that the point (7,10) is a true solution for the model.






Download pdf
8 0
2 years ago
Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t
zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

<em>Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.</em>

<em>(a) How many different groups of 5 problems can be chosen from the 12</em>

<em>problems?</em>

<em>(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?</em>

<u>In (a)</u>

<u></u>

Apply the formula

\frac{n!}{(n-r)!(r!)}

where n=12 and r=5

substitute values

=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792

In (b)

If Jerry did only 5 problems of one assignment then the probability  will be

\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}

<em />

<em />

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2 years ago
Suppose that 3% of the 2 million high school students who take the SAT each year receive special accommodations because of docum
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Answer:

See attachment for detailed answer.

Step-by-step explanation:

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8 0
2 years ago
Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
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Answer:

<h3>- 128 Superscript StartFraction 3 Over x EndFraction </h3><h3>- (4RootIndex 3 StartRoot 2 EndRoot)x </h3><h3>- (4 (2 Superscript one-third Baseline) ) Superscript x</h3><h3>Step-by-step explanation:</h3>

Given the indicinal equation (\sqrt[3]{128} )^{x}\\

According to one of the law of indices,

(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}

Applying this law to the question;

(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )

The following are therefore true based on the following calculation

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

5 0
2 years ago
Read 2 more answers
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