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V125BC [204]
2 years ago
4

The pressure of air in a 2.25 L container is 1.20 atm. What is the new pressure if the sample is transferred to a 6.50 L contain

er? Temperature is constant.
Chemistry
1 answer:
dolphi86 [110]2 years ago
6 0
Boyle's law gives the relationship between pressure of gas and volume.
It states that for a fixed amount of gas at constant temperature, pressure of gas is inversely proportional to volume.
PV = k
where P - pressure , V - volume and k - constant 
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are given on the right side of the equation.
substituting the values in the equation;
1.20 atm x 2.25 L = P x 6.50 L
P = 0.415 atm
new pressure is 0.415 atm 
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Which one is balanced or unbalanced force 1. Change object motion 2. Push or pull 3. Have direction 4. Do not change objects mot
Margaret [11]

Answer:

Explanation:

1. Change object motion - unbalanced force

2. Push or pull - Balanced forces do not cause a change in motion. When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces. So if object move it is unbalanced.

3. Have direction - unbalanced force

4. Do not change objects motion - balanced force

5. Net force does not =0 - unbalanced force

6.net force =0 - balanced force

3 0
2 years ago
In order for fission reactions to be successful, they must be self-perpetuating, meaning they must be able to keep themselves go
aleksandrvk [35]

Answer:

Option C is correct.

The minimum amount of material that is needed for a fission reaction to keep going is called the critical mass.

Explanation:

Nuclear fission is the term used to describe the breakdown of the nucleus of a parent isotope into daughter nuclei.

Normally, the initial energy supplied for nuclear fission is the energy to initiate the first breakdown of the first set of radioactive isotopes that breakdown. Once that happens, the energy released from the first breakdown is enough to drive further breakdown of numerous isotopas in a manner that leads to more energy generation.

But, for this to be able to be sustained and not fizzle out, a particular amount of radioactive material to undergo nuclear fission must be present. This particular amount is termed 'critical mass'

Hope this Helps!!!

3 0
2 years ago
Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
cluponka [151]
First you should know that there is seven oxygen atoms in one Mn2O7
So 
2.00 moles of Mn2O7 contain 14.00 moles of oxygen...
Then you multiply this no. with Avagadro no....
from formula
Number of moles= no. of particles/avagadro's no..
14.00×6.02×10²³=84.28 atoms of oxygen... 
7 0
2 years ago
In a study of the decomposition of the compound XX via the reaction
Leya [2.2K]

Answer:

( About ) 0.03232 M

Explanation:

Based on the units for this reaction it should be a second order reaction, and hence you would apply the integrated rate law equation "1 / [X] = kt + 1 / [X_o]"

This formula would be true for the following information -

{ X_o = the initial concentration of X, k = rate constant, [ X ] = the concentration after a certain time ( which is what you need to determine ), and t = time in minutes }

________

Therefore, all we have left to do is plug in the known values. The initial concentration of X is 0.467 at a time of 0 minutes, as you can tell from the given data. This is not relevant to the time needed in the formula, as we need to calculate the concentration of X after 18 minutes ( time = 18 minutes ). And of course k, the rate constant = 1.6

1 / [X] = ( 1.6 )( 18 minutes ) + 1 / ( 0.467 ) - Now let's solve for X

1 / [X] = 28.8 + 1 / ( 0.467 ),

1 / [X] = 28.8 + 2.1413...,

1 / [X] = 31,

[X] = 1 / 31 = ( About ) 0.03232 M

Now for this last bit here you probably are wondering why 1 / 31 is not 0.03232, rather 0.032258... Well, I did approximate one of the numbers along the way ( 2.1413... ) and took the precise value into account on my own and solved a bit more accurately. So that is your solution! The concentration of X after 18 minutes is about 0.03232 M

3 0
2 years ago
Which resonance structure would most likely create the infrared (IR) spectrum for the equilibrium geometry calculation of SCN −
rjkz [21]

Answer:

Resonance Structures for SCN-:[S-C N]-

Resonance StructureEnergy (kJ/mol)[S-C N]--23.00[S=C=N]

3 0
2 years ago
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