Let X is the random number Erik thinks of, and Y is the random number Nita thinks of.
Both X and Y are in the range from 0 to 20.
<span>X<=20
Y<=20
If the difference between their two numbers is less than 10, then Erik wins.
The difference between the two numbers can be written X-Y, or Y-X depending on which number (X or Y) is greater. But we do not know that. In order not to get negative value, we calculate absolute value of X-Y, written |X-Y| which will give positive value whether X is greater than Y or not.
If |X-Y|<10 Erik wins.
</span><span>If the difference between their two numbers is greater than 10, then Nita wins.
</span><span>If |X-Y|>10 Nita Wins
</span>
Question:
The square of a number decreased by 3 times the number is 28 find all possible values for the number
Answer:
The possible values of number are 7 and -4
Solution:
Given that the square of a number decreased by 3 times the number is 28
To find: all possible values of number
Let "a" be the unknown number
From given information,
square of a number decreased by 3 times the number = 28
Let us solve the above quadratic equation
Using the above formula,
Thus the possible values of number are 7 and -4
Answer:
D. There is not enough evidence at the 5% significance level to indicate that one route gets Katy to work faster, on average, since 0 falls within the bounds of the confidence interval.
Step-by-step explanation:
At 5% confidence level, Katy found difference in mean commuting times (Route 1-Route 2) in minutes as (-1,9).
Since no difference in means (0 min) falls within the confidence level (-1,9), we can not reject the hypothesis that there is no difference in mean commuting times when using Route1 or Route2.
A <em>higher</em> significance level(10% etc) may lead a <em>shorter</em> confidence interval leaving 0 outside and may reach a conclusion that Route1 takes longer than Route2
Jason has x dollars, and Ryan has 5 more dollars than Jason. How many dollars does Ryan have? How many dollars do both boys have?
Jason has x
Ryan has x + 5
both boys have x + x + 5 = 2x + 5
