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kompoz [17]
2 years ago
7

What additional information could be used to prove ΔEFG ΔE'F'G' using AAS? Check all that apply. EG = 12 and E'G' = 12 FG = 15 a

nd F'G' = 15 EF = 10 and E'F'= 12 m∠G = 42° and m∠G' = 42° EG ≅ E'G
Mathematics
2 answers:
Dafna1 [17]2 years ago
5 0

By definition, congruent triangles should have all the corresponding sides and all the corresponding angles equal or congruent to each other. Thus, in the given question, all corresponding sides and angles of ΔEFG and ΔE'F'G' should be congruent. But, as we can see clearly it is given that, EF = 10 and E'F'= 12, thus, the corresponding sides EF and E'F' are not equal. Thus, we can never prove that:

\Delta EFG\cong\Delta E'F'G'

Thus, \Delta EFG\ncong\Delta E'F'G'

steposvetlana [31]2 years ago
5 0
1. EG = 12 and E'G' = 12
2: FG = 15 and F'G' = 15
5: EG <span>≅ E'G'</span>
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Answer: see the graphic

Step-by-step explanation:

A. Type I error helps us to conclude that the flight is not profitable, when in fact it is profitable.

B. a = 0.05

C. Type II error does not show that the flight is profitable

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2 years ago
Two sides of a triangle have lengths 12 m and 14 m. The angle between them is increasing at a rate of 2°/min. How fast is the le
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Answer:

1.692 m/min

Step-by-step explanation:

Let \theta be the angle between the two sides and x be the length of the third side. By cosine rule,

x^2 = 12^2+14^2-2\times12\times14\cos\theta = 340 - 336\cos\theta

x= \sqrt{340 - 336\cos\theta}

We differentiate x with respect to \theta by applying chain rule.

\dfrac{dx}{d\theta} = \dfrac{336\sin\theta}{2\sqrt{340 - 336\cos\theta}} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}}

Rate of change of \theta is 2

\dfrac{\theta}{dt} = 2

Rate of change of x is

\dfrac{dx}{dt} = \dfrac{dx}{d\theta}\times\dfrac{d\theta}{dt}

\dfrac{dx}{dt} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}} \times2=\dfrac{336\sin\theta}{\sqrt{340 - 336\cos\theta}}

At 60°,

\dfrac{dx}{dt} = \dfrac{336\sin60}{\sqrt{340 - 336\cos60}} = 1.692 \text{ m/min}

4 0
1 year ago
Hubert wants to buy a car tire that has a full price of$245 plus an 8% sales tax. Which is the better offer, a 15%-off sale or a
tekilochka [14]
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6 0
2 years ago
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The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2
Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in ^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15 ways.

The probability of getting two 3 as outcome is \frac{1}{4} \times\frac{1}{4} = \frac{1}{16}.

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is 1 - \frac{1}{4} = \frac{3}{4}.

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4 0
2 years ago
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
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Answer:

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The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

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replacing;

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Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

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One cement bridge post weighs 9,135 pounds

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