Let r = usual driving rate
let t = usual driving time
We need to figure out t
The distance she covers in her usual time at her usual rate is r*t
The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)
Set this equal to each other and solve for t.
rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2
So her usual time is 2 hours. (There's probably a faster way to do this)
Use equation
Question 1: Need to find A:
Question 2: Need to find t, use LOGARITHM:
A=35000
P=49339
So 2010+32 =
2042.
Answer:
Ruby’s function notation V(h) describes the volume of the pool after h number of hours. Hours is the independent variable and the total volume is the dependent variable.
Step-by-step explanation:
sample response
Answer:
Rs.64
Step-by-step explanation:
<u>Amount of oranges:</u>
<u>Oranges sold:</u>
<u>Money made:</u>
<u>Selling price of 150 kg:</u>
<u>Cost price:</u>
- x+10% = 70.4
- x*1.1= 70.4
- x= 70.4/1.1
- x= Rs.64
- Cost price of oranges= Rs. 64
