Answer:
A and D
Step-by-step explanation:
Here, we shall be evaluating the validity of the statements;
A. Yes, A is true
There are four even numbers 2,4,6 and 8 and 4 odd number 1,3,5,7; The landing should be equal at 125 each
B. This is wrong
It is supposed to land half of the number of time s which is half of 250 and that is 125
C.This is wrong
The numbers greater than 4 are 5,6,7,8
Now, the probability should be 4/8 = 1/2 and that is 50%
D. This is correct
Number of times we have a landing on odd numbers is 250-135 = 115
The experimental probability of landing on an odd number is thus 115/250 = 0.46 which is 46%
That's a lot of money and words. I don't appreciate this. I would probably just break down and cry tbh
Answer:
Option E) 61.6
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100 bushels per acre
Standard Deviation, σ = 30 bushels per acre
We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.
Formula:
P(X>x) = 0.90
We have to find the value of x such that the probability is 0.90
P(X > x)
Calculation the value from standard normal table, we have,
Hence, the yield of 61.6 bushels per acre or more would save the seed.
Denise is constructing A square.
Note: A square has all sides equal.
We already given two vertices M and N of the square.
And another edge of the square is made by from N.
Because a square has all sides of equal length, the side NO should also be equal to MN side of the square.
Therefore, <em>Denise need to place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass. That would make the NO equals MN.</em>
Therefore, correct option is :
D) place the point of the compass on point N and draw an arc that intersects N O, using MN as the width for the opening of the compass.
