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2 years ago

13

Please please please Factor 9x - 27xy

1 answer:

Kamila [148]2 years ago

7 0

Common factor of 3x

3x ( 3x+9xy)( 1+0)

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Atley, Bradley, Cursen, and Drake are the married names of Kermit, Leonard, Marlene, and Norma. Read the clues to find each pers

vodka [1.7K]

This is how the chart will look like:
Kermit Leonard Marlene Norma
Atley

Bradley

Cursen

Drake

1. Drake is Bradley's sister.
2. Cursen is Atley's brother
3. Norma and Drake are not related
<span>4. Kermit is a year older than Bradley
</span>
Drake is a girl (1), but she is not related to Norma(3), So she is Marlene.
1) MARLENE DRAKE

Drake and Bradley are related; Norma is not related to them(3). Norma can either be Atley or Cursen. But, Cursen is Male. So, Norma is NORMA ATLEY

Remaining family names are Bradley and Cursen. Kermit is not a Bradley, so he is KERMIT CURSEN. That leaves LEONARD BRADLEY.

5 0

2 years ago

Read 2 more answers

One brand of cookies is sold in three different box sizes: small, medium, and large. The small box has half the volume of the me

lozanna [386]

Answer:

a

Step-by-step explanation:

6 0

2 years ago

*PLEASE ANSWER ASAP* John is playing a game with two friends. Using the spinner pictured, one friend spun a three, and the other

levacccp [35]

Answer:

3

Step-by-step explanation:

he wants a 6,7,or8

5 0

2 years ago

Let n be an integer in the conditional statement below.

statuscvo [17]

Answer:

The hypothesis is: "The last digit of n is zero."

The conclusion is: "n is divisible by five."

The converse is: "If n is divisible by five, the the last digit of n is zero."

The contrapositive is: "If n is not divisble by five, then n does not end in zero."

Step-by-step explanation:

I just took the test :)

5 0

2 years ago

A tank contains 500 gallons of salt-free water. A brine containing 0.25 lb of salt per gallon runs into the tank at the rate of

Neporo4naja [7]

Answer:

0.0198 lbs per gallon

Step-by-step explanation:

amount of salt free water = 500 gallons

salt rate in = 1 gal/min

salt rate out = 1 gal/min

amount o salt in brine = 0.25 lb per gallon

Let the amount of salt in the tank be A(t) at any time t.

$\frac{dA(t)}{dt} =salt rate in - salt rate out$

salt rate in = 0.25 x 1 = 0.25

salt rate out = $\frac{A(t)\times 1}{500}$

The differential equation is given by

$\frac{dA(t)}{dt} =1 - \frac{A(t)\times 1}{500}$

where, A(0) = 0

So, the equation becomes

$\frac{dA(t)}{dt} + \frac{A(t)}{500} = 1$

Here the integrating factor is $e^{\frac{dt}{500}}=e^{\frac{t}{500}}$

The solution of the above differential equation is given by

$A(t)\times e^{\frac{t}{500}} = \int e^{\frac{t}{500}}dt$

$A(t)\times e^{\frac{t}{500}} = 500\times e^{\frac{t}{500}}+C$

where, C is the integrating constant.

$A(t)=500+Ce^{-\frac{t}{500}}$

Put, A(0) = 0

C = - 500

$A(t)=500\left ( 1-e^{-\frac{t}{500} \right )$

As concentration is defined as

Concentration = Quantity / Volume

$C(t)=\frac{A(t)}{500}$

$C(t)=1-e^{\frac{-t}{500}}$

Now concentration at t = 10 min

Put, t = 10 min

$C(10)=1-e^{\frac{-10}{500}}$

C (10) = 0.0198 lbs per gallon

Thus, teh concentration after 10 min is 0.0198 lbs per gallon.

7 0

2 years ago