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Alinara [238K]
2 years ago
15

The most common data link layer protocol for wired connections is _____.

Computers and Technology
1 answer:
harkovskaia [24]2 years ago
7 0

The answer is Ethernet

Ethernet is by far the most popular LAN by a mile. It is a group of protocols that work at either the Data link layer or the Physical layer of the OSI model. Ethernet in the engineering world is defined as the IEEE 802.3 specification.






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Find true or false. A hacker is hacking software with access in sensitive information from your computer​
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ITS TRUE!!I SEARCHED IT
7 0
1 year ago
Select the correct text in the passage.
aliina [53]

Answer: When was admitted, hospital authorities recorded his medical history. Then, placed in an ICU where his vital signs were constantly monitored.

Explanation: With the help of computers, medical histories are often kept in the computer for future reference. Machines are connected to computers to record vital signs.

4 0
2 years ago
Jim is writing a program to calculate the wages of workers in a teddy bear factory.
34kurt

Answer:

The algorithm is as follows;

1. Start

2. Input TeddyBears

3. Input Hours

4. WagebyTeddy = 2 * TeddyBears

5. WagebyHour = 5 * Hours

6. If WagebyHour > WagebyTeddy then

6.1 Print WagebyHour

7. Else

7.1. Print WagebyTeddy

8. Stop

Explanation:

The following variables are used;

TeddyBears -> Number of teddy bears made

Hours -> Number of Hours worked

WagebyTeddy -> Wages for the number of teddy bears made

WagebyHour -> Wages for the number of hours worked

The algorithm starts by accepting input for the number of teddy bears and hours worked from the user on line 2 and line 3

The wages for the number of teddy bears made  is calculated on line 4

The wages for the number of hours worked  is calculated on line 5

Line 6 checks if wages for the number of hours is greated than wages for the number of bears made;

If yes, the calculated wages by hour is displayed

Otherwise

the calculated wages by teddy bears made is displayed

3 0
2 years ago
Create the class named SortFile. The class will have a single attribute, which is an ArrayList of integers. The class will have
S_A_V [24]

Answer:

See explaination

Explanation:

//SortFile.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

public class SortFile {

// array list of integers to store the numbers

private ArrayList<Integer> list;

// default constructor

public SortFile() {

// initializing list

list = new ArrayList<Integer>();

// reading file name using a scanner

Scanner sc = new Scanner(System.in);

System.out.print("Enter file name: ");

String filename = sc.nextLine();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

// opening file

sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

// closing file

sc.close();

} catch (FileNotFoundException e) {

// exception occurred.

System.err.println(e);

}

}

// constructor taking a file name

public SortFile(String filename) {

// initializing list

list = new ArrayList<Integer>();

// opening file inside a try catch block. if you want to throw exception

// instead, just remove try-catch block and add throws

// FileNotFoundException to the method signature.

try {

Scanner sc = new Scanner(new File(filename));

// looping and reading each integer from file to list

while (sc.hasNextInt()) {

list.add(sc.nextInt());

}

sc.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

}

// method to return a sorted array of integers containing unique elements

// from list

public int[] sort() {

// creating an array of list.size() size

int arr[] = new int[list.size()];

// count of unique (non duplicate) numbers

int count = 0;

// looping through the list

for (int i = 0; i < list.size(); i++) {

// fetching element

int element = list.get(i);

// if this element does not appear before on list, adding to arr at

// index=count and incrementing count

if (!list.subList(0, i).contains(element)) {

arr[count++] = element;

}

}

// now reducing the size of arr to count, so that there are no blank

// locations

arr = Arrays.copyOf(arr, count);

// using selection sort algorithm to sort the array

int index = 0;

// loops until index is equal to the array length. i.e the whole array

// is sorted

while (index < arr.length) {

// finding the index of biggest element in unsorted array

// initially assuming index as the index of biggest element

int index_max = index;

// looping through the unsorted part of array

for (int i = index + 1; i < arr.length; i++) {

// if current element is bigger than element at index_max,

// updating index_max

if (arr[i] > arr[index_max]) {

index_max = i;

}

}

// now we simply swap elements at index_max and index

int temp = arr[index_max];

arr[index_max] = arr[index];

arr[index] = temp;

// updating index

index++;

// now elements from 0 to index-1 are sorted. this will continue

// until whole array is sorted

}

//returning sorted array

return arr;

}

//code for test-run

public static void main(String[] args) {

//initializing SortFile using default constructor

SortFile sortFile = new SortFile();

//displaying sorted array

System.out.println(Arrays.toString(sortFile.sort()));

}

6 0
2 years ago
While in an interactive nslookup session, you'd use the ______ keyword to change the DNS server you're using
serious [3.7K]
Hostname is assigned to a device that would be connected to the computer network and thus would help in identifying the form of electronic communication. While in an interactive nslookup session, one would use the DMNNAMSVR keyword to change the DNS server one is using.
4 0
2 years ago
Read 2 more answers
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