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PIT_PIT [208]
2 years ago
12

Write c++ program bmi.cpp that asks the user bmi.cpp the weight (in kilograms) and height (in meters).

Computers and Technology
1 answer:
Galina-37 [17]2 years ago
8 0

Answer:

// here is code in C++(bmi.cpp).

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

float weight,height;

cout<<"enter the weight(in kilograms):";

//read the weight

cin>>weight;

cout<<"enter the height(in meters):";

//read the height

cin>>height;

// calculate the bmi

float bmi=weight/(pow(height,2));

// print the body-mass index with two decimal places

cout<<"BMI is: "<<fixed<<setprecision(2)<<bmi<<endl;

return 0;

}

Explanation:

Read the weight from user and assign it to variable "weight",read height and assign it to variable "height".Then find the body-mass index as (weight/height^2).Here weight  should be in kilograms and height should be in meters.

Output:

enter the weight(in kilograms):75

enter the height(in meters):1.8

BMI is: 23.15

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For the (pseudo) assembly code below, replace X, Y, P, and Q with the smallest set of instructions to save/restore values on the
Dimas [21]

Answer:

Explanation:

Let us first consider the procedure procA; the caller in the example given.

  Some results: $s0,$s1,$s2, $t0,$t1 and $t2 are being stored by procA. Out of these registers, few registers are accessing by procA after a call to procB. But, procB might over-write these registers.

       Thus, procA need to save some registers into stack first before calling procB, .

      only $s1,$t0 and $t1 are being used after return from procB in the given example,

       Caller saves and restores only values in $t0-$t9, according to MIPS guidelines for caller-saved and callee-saved registers, .

       Thus, procA needs to save only $t0 and $t1.

    jal instruction overwrites the register $ra by writing the address, to which the control should jump back, after completing the instructions of procB, when procB is called,.

       Therefore, procA also need to save $ra into stack.

 ProcA is writing new values into $a0,$a2, procA must save $a0 and $a1 first before calling procB, .

     In the given example, after return from procB, only $a0 is being used. It is therefore enough to save $a0.

   Also, procA needs to save frame pointer, which points the start of the stack space for each procedure.

       Generally, as soon as the procedure begins, frame pointer is set to the current value of the stack pointer,.

Let us consider the procedure procB; the callee in the given example.

 The callee is responsible for saving values in $s0-$s7 and restoring them before returning to caller, this is according to MIPS guidelines for caller-saved and callee-saved registers,

   procB is expected to over-write the registers $s2 and $t0. Nonetheless, in the first two lines, procB might over-write the registers $s0 and $s1.

   Thus, procB is responsible for saving and restoring $s0,$s1 and $s2.

X:

We need to create space for 5 values on the stack since procA needs to save $a0,$ra,$t0,$t1 and $fp(frame pointer), . Each value(word) takes 4 bytes.

$sp = $sp – 20 # on the stack, create space for 5 values

sw $a0, 16($sp) # store the result in $a0 into the memory address

               # indicated by $sp+20

sw $ra, 12($sp) # save the second value on stack

sw $t0, 8($sp) # save the third value on stack

sw $t1, 4($sp) # save the fourth value on stack

sw $fp, 0($sp) #  To the stack pointer, save the frame pointer

$fp = $sp      #  To the stack pointer, set the frame pointer

Y:

lw $fp, 0($sp) #  from stack, start restoring values

lw $t1, 4($sp)

lw $t0, 8($sp)

lw $ra, 12($sp)

lw $a0, 16($sp)

$sp = $sp + 20 # decrease the size of the stack

P:

$sp = $sp – 12 #  for three values, create space on the stack

sw $s0, 0($sp) # save the value in $s0

sw $s1, 0($sp) # save the value in $s1

sw $s2, 0($sp) # save the value in $s2

Q:

lw $s0, 0($sp) #  from the stack, restore the value of $s0

lw $s1, 0($sp) #  from the stack, restore the value of $s1

lw $s2, 0($sp) #  from the stack, restore the value of $s2

$sp = $sp + 12 # decrease the stack size

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In 2007, __________ Floridians were injured in alcohol-related collisions.
vovangra [49]

21

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2 years ago
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2 years ago
____________ is defined as the set of activities that revolve around a new software product, from its inception to when the prod
Elis [28]

Answer:

The answer is Application Lifecycle Management

Explanation:

Application lifecycle management is the complete handling and management of computer software programs from inception till it is retired.

It covers various aspects like requirement gathering management; software architecture; software programming, testing, and maintenance; change management, with continuous integration, release management, upgrades, deployment and so-on.

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C# Write, compile, and test a program named PersonalInfo that displays a person’s name, birthdate, work phone number, and cell p
Soloha48 [4]

Answer:

#include <stdio.h>

#Include<iostream>

using namespace std;

//Define required function

PersonalInfo( )   {

    printf("Name   : Robert Josh\n");  

    printf("DOB    : July 14, 1975\n");  

    printf("Work Phone : 00-00000000\n");  

    printf("Cell Phone : 11-777777777\n");  

    return(0);  

 }

int main()   {

    //Call function

 PersonalInfo( );

 return 0;

 }

Explanation:

Its just a simple code to print required details when the function PersonalInfo is called.

5 0
2 years ago
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