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Assoli18 [71]
2 years ago
10

An employer may conduct an aptitude test to check for what? A. Your ability to solve problems B. Test your actual skills, such a

s typing C. Discover individual behavior patterns D. The capacity to acquire certain skills
Mathematics
2 answers:
MariettaO [177]2 years ago
8 0

The <em><u>correct answer</u></em> is:

B. Test your actual skills, such as typing

Explanation:

There are four different types of aptitude tests.

Skills tests are usually easy tasks relating to an important function of the job, such as typing speeds or data entry.

Knowledge tests are designed to measure how much a prospective employee knows about a particular aspect of the job to ensure he or she has the required level of knowledge for the job.  

Ability tests are used to measure cognitive or mental ability, and are based on presenting candidates with workplace scenarios and asking them to explain what they would do in a particular situation.

The most commonly used personality tests measure five basic factors of personality – openness to experience, extroversion, agreeableness, conscientiousness, and emotional stability.  This is often used for sales positions to predict performance.

Darya [45]2 years ago
5 0
The correct answers should be A. Your ability to solve problems

Aptitude tests often deal with solving issues using logical reasoning and behavior when solving problems.
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The surface areas of two similar figures are 4 in2 and 9 in2. If the volume of the larger figure is 216 in3, what is the volume
OverLord2011 [107]
We know that
surface area smaller figure=scale factor²*surface area larger figure
scale factor=√[surface area smaller figure/surface area larger figure]
scale factor=√[4/9]-----> scale factor=2/3
so
volume smaller figure=scale factor³*volume larger figure
volume smaller figure=(2/3)³*216----> (8/27)*216----> 64 in³

the answer is
the volume of the smaller figure is 64 in³
8 0
2 years ago
Which expression is equivalent to –21.8 – (–18.3)?
Rina8888 [55]

Answer:

–21.8 – 18.3

Step-by-step explanation:

because you keep change flip

4 0
2 years ago
Read 2 more answers
A bunch bowl is in the shape of a hemisphere. The top rim has a circumference of 116cm.
Tom [10]
The hemisphere is half the volume of a sphere. Since we are given the circumference, we can solve for the radius of the sphere. That is 
     C=2\pi r

     116\:cm=2\pi r

     r=\frac{116}{2\pi }=18.462\:cm

Part A
We can now compute for the volume of the hemisphere.
     V=\frac{1}{2}\times \frac{4}{3}\pi r^3=\frac{1}{2}\times \frac{4}{3}\pi \left(18.462\right)^3=13179\:cm^3

Part B
We just need to convert the volume into its corresponding gallons
     13179\:cm^3\times \frac{1\:Liter}{1000\:cm^3}\times \frac{1\:gallon}{3.785\:Liters}=3.5\:gallons
8 0
2 years ago
Which is a zero of the quadratic function f(x)9x^2-54x-19
zvonat [6]

Answer:

X= -1/3, X= 19/3

Step-by-step explanation:

3 0
2 years ago
Three couples and two single individuals have been invited to an investment seminar and have agreed to attend. Suppose the proba
Maksim231197 [3]

Answer:

(a) Probability mass function

P(X=0) = 0.0602

P(X=1) = 0.0908

P(X=2) = 0.1704

P(X=3) = 0.2055

P(X=4) = 0.1285

P(X=5) = 0.1550

P(X=6) = 0.1427

P(X=7) = 0.0390

P(X=8) = 0.0147

NOTE: the sum of the probabilities gives 1.0068 for rounding errors. It can be divided by 1.0068 to get the adjusted values.

(b) Cumulative distribution function of X

F(X=0) = 0.0602

F(X=1) = 0.1510

F(X=2) = 0.3214

F(X=3) = 0.5269

F(X=4) = 0.6554

F(X=5) = 0.8104

F(X=6) = 0.9531

F(X=7) = 0.9921

F(X=8) = 1.0068

Step-by-step explanation:

Let X be the number of people who arrive late to the seminar, we can assess that X can take values from 0 (everybody on time) to 8 (everybody late).

<u>For X=0</u>

This happens when every couple and the singles are on time (ot).

P(X=0)=P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot)\\\\P(X=0)=(1-0.43)^{5}=0.57^5= 0.0602

<u>For X=1</u>

This happens when only one single arrives late. It can be #4 or #5. As the probabilities are the same (P(#4=late)=P(#5=late)), we can multiply by 2 the former probability:

P(X=1) = P(\#4=late)+P(\#5=late)=2*P(\#4=late)\\\\P(X=1) = 2*P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=late)*P(\#5=ot)\\\\P(X=1) = 2*0.57*0.57*0.57*0.43*0.57\\\\P(X=1) = 2*0.57^4*0.43=2*0.0454=0.0908

<u>For X=2</u>

This happens when

1) Only one of the three couples is late, and the others cooples and singles are on time.

2) When both singles are late , and the couples are on time.

P(X=2)=3*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=ot)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=2)=3*(0.43*0.57^4)+(0.43^2*0.57^3)=0.1362+0.0342=0.1704

<u>For X=3</u>

This happens when

1) Only one couple (3 posibilities) and one single are late (2 posibilities). This means there are 3*2=6 combinations of this.

P(X=3)=6*(P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=3)=6*(0.43^2*0.57^3)=6*0.342=0.2055

<u>For X=4</u>

This happens when

1) Only two couples are late. There are 3 combinations of these.

2) Only one couple and both singles are late. Only one combination of these situation.

P(X=4)=3*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=ot)*P(\#5=ot))+P(\#1=l)*P(\#2=ot)*P(\#3=ot)*P(\#4=l)*P(\#5=l)\\\\P(X=4)=3*(0.43^2*0.57^3)+(0.43^3*0.57^2)\\\\P(X=4)=3*0.0342+ 0.0258=0.1027+0.0258=0.1285

<u>For X=5</u>

This happens when

1) Only two couples (3 combinations) and one single are late (2 combinations). There are 6 combinations.

P(X=6)=6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=6*(0.43^3*0.57^2)=6*0.0258=0.1550

<u>For X=6</u>

This happens when

1) Only the three couples are late (1 combination)

2) Only two couples (3 combinations) and one single (2 combinations) are late

P(X=6)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=ot)*P(\#5=ot)+6*(P(\#1=l)*P(\#2=l)*P(\#3=ot)*P(\#4=l)*P(\#5=ot))\\\\P(X=6)=(0.43^3*0.57^2)+6*(0.43^4*0.57)\\\\P(X=6)=0.0258+6*0.0195=0.0258+0.1169=0.1427

<u>For X=7</u>

This happens when

1) Only one of the singles is on time (2 combinations)

P(X=7)=2*P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=ot)\\\\P(X=7)=2*0.43^4*0.57=0.0390

<u>For X=8</u>

This happens when everybody is late

P(X=8)=P(\#1=l)*P(\#2=l)*P(\#3=l)*P(\#4=l)*P(\#5=l)\\\\P(X=8) = 0.43^5=0.0147

8 0
2 years ago
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