What is the permutations of the letters in the word football?

An account with a $250 balance accrues 2% annually. If no deposits or withdrawals are made, which graph can be used to determine

ollegr [7]

Answer:

7 years

Step-by-step explanation:

Because there is no graph, I will just tell you how many years it should take, and you can probably figure it out from there. To start, let's [get out a calculator] find out what 2% of 250 is. This is 5, so we can add 5. Notice that adding 5 to the number does not change 2% of it by much, only by 5/50 or 0.1. So, we can keep adding until we get above 282, which should take 285 minus 250 over 5 times, or 7. So, the answer is 7 years. You can [get out a calculator] and find out that it is indeed 7 years.

5 0

2 years ago

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Shishir bought 4000 orange at 70 paisa each. But 400 of them were rotten. He sold 2000 oranges at 90 paisa each.If he plans to m

Ipatiy [6.2K]

Answer:

He needs to sell the rest of the oranges at 75 paisa each.

Step-by-step explanation:

Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

Note: 1 rupees = 100 paisa

Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

2000×0.90 rupees = 1800 rupees

The number of oranges now Shishir have:

4000 - 2000 - 400 = 1600

He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

2800 rupees + 200 rupees = 3000 rupees

He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:

3000 rupees - 1800 rupees = 1200 rupees

Therefore, the cost of one orange is:

1600 oranges = 1200 rupees

1 orange = 1200/1600 rupees

1 orange = 0.75 rupees

Hence, he needs to sell the rest of the oranges at 75 paisa each.

4 0

2 years ago

The binomial (y − 2) is a factor of y2 − 10y + 16. What is the other factor?

PtichkaEL [24]

Answer:

$\left(y-8\right)$

Step-by-step explanation:

$y^2-10y+16$

$=\left(y^2-2y\right)+\left(-8y+16\right)$

$y^2-2y$

$=yy-2y$

$=y\left(y-2\right)$

$-8y+16$

$=-8y+8\cdot \:2$

$=-8\left(y-2\right)$

$=y\left(y-2\right)-8\left(y-2\right)$

$=\left(y-2\right)\left(y-8\right)$

The other factor is:

$\left(y-8\right)$

5 0

2 years ago

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Jude says that the volume of a square pyramid with base edges of 7 in and a height of 7 in is equal to the volume of a cylinder

irakobra [83]

Answer:

Jude is not correct

Step-by-step explanation:

The volume of a square pyramid is given as:

$V = a^2\frac{h}{3}$

where a = base edge and h = height

Hence, the volume of the square pyramid with base edge of 7 in and height of 7 in is:

$V = 7^2*\frac{7}{3}$

V = $114.3 in^3$ ≅ $114 in^3$

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius and h = height

Hence, the volume of a cylinder with radius of 7 in and height of 7 in is:

$V = \pi *7^2*7$

V = $1077.57 in^3$ ≅ $1078 in^3$

Since their volumes are not equal, Jude is not correct.

8 0

2 years ago

About how many more inches of rain did Asheville get than Wichita? About how many more days did it rain in Asheville than Wichit

zaharov [31]

Answer:

Par 1) 19.10 inches

Part 2) 39 days

Step-by-step explanation:

we know that

Asheville

47.71 in

124 days

Wichita

28.61 in

85 days

Part 1) About how many more inches of rain did Asheville get than Wichita?

In this part subtract the number of inches of rain in Wichita from the number of inches of rain in Asheville

so

$47.71-28.61=19.10\ in$

Part 2) About how many more days did it rain in Asheville than Wichita?

n this part subtract the number of days of rain in Wichita from the number of days of rain in Asheville

so

$124-85=39\ days$

4 0

2 years ago