Question

Jude says that the volume of a square pyramid with base edges of 7 in and a height of 7 in is equal to the volume of a cylinder with a radius of 7 in and a height of 7 in. Jude rounded all answers to the nearest whole number. Examine Jude's calculations. Is he correct?

Answer 1

Answer:

Jude is not correct

Step-by-step explanation:

The volume of a square pyramid is given as:

$V = a^2\frac{h}{3}$

where a = base edge and h = height

Hence, the volume of the square pyramid with base edge of 7 in and height  of 7 in is:

$V = 7^2*\frac{7}{3}$

V = $114.3 in^3$ ≅ $114 in^3$

The volume of a cylinder is given as:

$V = \pi r^2h$

where r = radius and h = height

Hence, the volume of a cylinder with radius of 7 in and height of 7 in is:

$V = \pi *7^2*7$

V = $1077.57 in^3$ ≅ $1078 in^3$

Since their volumes are not equal, Jude is not correct.