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Harlamova29_29 [7]
2 years ago
4

From a hot air balloon, the angle between a radio antenna straight below and the base of the library downtown is 63°, as shown b

elow. If the distance between the radio antenna and the library is 24 miles, how many miles high is the balloon?

Mathematics
1 answer:
Softa [21]2 years ago
8 0
This is a problem on right triangle trigonometry. The given angle is 63 degrees, the 24 miles distance is opposite this angle, and the unknown distance is adjacent to this angle. Therefore, we use the tangent function. That is 

     tan\left(63^{\circ} \right)=\frac{24\:miles}{h}

     h=\frac{24}{tan\:63^{\circ} }=12.22\:miles
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Victor baked 30 chocolate chip cookies,18 peanut butter cookies, and 24 sugar cookies. He wants to split them up into equal and
mylen [45]

Answer:

He can make 6 groups

Step-by-step explanation:

To solve this problem first you need to find the GCF or greatest common factor. Now you can put 5 chocolate chip cookies in each group, 3 peanut butter, and 4 sugar cookies. These are all relatively prime so that would be your final answer.

7 0
2 years ago
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.
Darina [25.2K]

Answer:

There is no solution for the given radical equation.

x = 225/16 is an extraneous solution.

Step-by-step explanation:

The given equation is  

Add 3 to both sides of the equation

Squaring both sides

Divide both sides by 16

Substituting back the value of x in original equation to check the extraneous solution.

 

Since -18≠ 12. Hence, the value of x does not satisfy the equation.

Therefore, x = 225/16 is an extraneous solution.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

8 0
2 years ago
A baker needs 8 1/2 cups of flour for a sheet cake recipe. He has 4 2/3 cups of flour in a canister and buys 5 1/4 cups more.
Juli2301 [7.4K]

Answer: 1 5/12 cups of flour leftover

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6 0
2 years ago
Find the common difference of the arithmetic sequence. 6,9.4,12.8,16.2
Blababa [14]

A sequence is said to be arithmetic if every couple of adjacent elements differ by the same number. If this is the case, that constant number is called the common difference.

This sequence is arithmetic, because the difference between every element and the previous one is

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  • 16.2 - 12.8 = 3.4

So, the common differnece is 3.4, because every couple of adjacent terms differ by 3.4

8 0
2 years ago
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