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2 years ago

On a spinner: P(3) = ⅜ and the p(4) = ⅓ What is the probability of getting 3 or 4

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

7 0

17/24 probability.

Also, how do you ask a question? I can't find the button.

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Mr Chua borrows a sum of money from the bank which charges a compound interest of 4.2% per annum, compounded 6.Given that Mr Chu

Inessa [10]

Answer:

Original sum of money = $2246.51

Step-by-step explanation:

Interest = $96.60

Interest is compounded 6 times in a year ; n = 6

time = 1 year ; Rate of interest (r) = 4.2%

Interest = Future Value - Principal Value ...........(1)

$\text{Future Value = }Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}\\\\\text{Substituting this value in equation (1) , We get }\\\\Interest=Principal\cdot (1+\frac{r}{100\times n})^{n\cdot t}-Principal\\\\\implies 96.60=Principal[\cdot (1+\frac{4.2}{100\times 6})^{6\cdot 1}-1]\\\\\implies Principal=\$2246.51$

Hence, the original sum of money borrowed = $2246.51

4 0

2 years ago

There are 5 cards with a picture of a rose and 1 card with a picture of a daisy. Olga keeps all the cards face down on the table

HACTEHA [7]

The correct answer is 4 over 5

4 0

2 years ago

Suppose babies born in a large hospital have a mean weight of 4095 grams, and a standard deviation of 569 grams. If 130 babies a

Butoxors [25]

Answer:

$P =0.3998$

Step-by-step explanation:

Let ${\overline{x}}$ be the average of the sample, and the population mean will be $\mu$

We know that:

$\mu = 4095$ gr

Let $\sigma$ be the standard deviation and n the sample size, then we know that the standard error of the sample is:

$E=\frac{\sigma}{\sqrt{n}}$

Where

$\sigma=569$

$n=130$

In this case we are looking for:

$P(|{\displaystyle{\overline{x}}}- \mu|>42)$

This is:

${\displaystyle{\overline{x}}}- \mu>42$ or ${\displaystyle{\overline{x}}}- \mu$

$P=P({\displaystyle{\overline{x}}}- \mu>42)+ P({\displaystyle{\overline{x}}}- \mu$

Now we get the z score

$Z=\frac{{\displaystyle{\overline{x}}}-\mu}{\frac{\sigma}{\sqrt{n}}}$

$P=P(z>\frac{42}{\frac{569}{\sqrt{130}}}) + P(z$

$P=P(z>0.8416) + P(z$

Looking at the tables for the standard nominal distribution we get

$P =0.1999+0.1999$

$P =0.3998$

6 0

2 years ago

Suppose that we want to investigate whether curfews correlate with differences in grades for students in middle school. We selec

Anton [14]

Answer:

Step-by-step explanation:

Hello!

Given the variables

X: Curfew of middle school students (Categorized Yes/No)

Y: Average grade of middle school students. (Categorized: A, B, C, and D)

The objective is to test if there is an association between both variables, you have to conduct a Chi-Square test of independence.

In the null hypothesis, you state that both variables are independent vs. the alternative hypothesis that the variables are dependent.

The hypotheses for this test are:

H₀: Pij= Pi. * P.j i= (1)Yes, (2)No; j= (1)A, (2)B, (3)C, (4)D

H₁: Te variables are not independent.

α: 0.05

$X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~X_{(r-1)*(c-1)}$

Where

Oij is the observed frequency for the i-row and j-column

Eij is the expected frequency for the i-row and j-column

r= number of categories in the rows

c= number of categories in the columns

$X^2_{H_0}= 1.4796703$

p-value: 0.687

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis. So using a 5% significance level, you can conclude that having a curfew and the average grades of middle schoolers are two independent variables.

3 0

2 years ago

5. A factory produces 24532 bulbs in a month. What is its annual<br> production?

maksim [4K]

Answer:

294384

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers