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2 years ago

Which metal can replace Cr in Cr2O3

Chemistry

2 answers:

slavikrds [6]2 years ago

8 0

The answer to this question is Aluminum.

densk [106]2 years ago

3 0

Answer:

Aluminium.

Explanation:

Hello,

In this case, the most appropriated metal turns out being the Aluminum since it is higher in the activity series than nickel. Don't forget that activity series is an empirical tool used to predict products in displacement reactions and reactivity of metals with water and acids in replacement reactions and ore extraction.

Best regards.

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Element z reacts with bromine to form an ionic compound zbr2

slamgirl [31]

Explanation:

Physical properties of ZBr₂

The compound is an ionic substance. Therefore it will have properties of ionic compounds. Some of these properties are:

it is a hard solid usually with high melting points or a liquid with high boiling points.
Soluble in water and insoluble in non-polar solvents.
It can conduct electricity in aqueous solutions or in molten form.
it will undergo a fast reaction.

Z is a metal

To form ionic compound, a metal will combine with a non-metal. Bromine is a non-metal and it is expected that Z will be a metal. This is because ionic bonds involves transfer of electron from one specie to the other. Metals are usually the donor and non-metals are the receptor. This is how ionic bond forms. The electrostatic attraction resulting from the ions produced the ionic bond.

Formula of the oxide

Z 0

+2 -2

It is obvious that Z has 2 valence electrons. It will lose the two valence electrons to attain stability.

Oxygen requires 2 electrons to resemble Neon. This combination will give a compound ZO.

Learn more:

ionic compounds brainly.com/question/6071838

#learnwithBrainly

5 0

2 years ago

Application of boyle's law a 12-liter tank contains helium gas pressurized to 160 atm. part b what size tank would be needed to

son4ous [18]

According to Mendeleyev-Klapeyronâ€™s equation pV = nRT, where p = 160 atm V = 12 R -constant 0.0821 & T = 298 in Kelvin Using given data, we can determine the amount of Helium gas: n = pV/RT = (160â™12)/(0,0821â™298) = 78,48 (mol) For atmospheric pressure (1 atm) and the same amount we can calculate the volume of tank, using previous equation: V = nRT/p = (78,48â™0,0821â™298)/1 = 1920 (liters) V = 1920 liters Thus Answer is 1920 liters

5 0

2 years ago

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces

Alchen [17]

The question is incomplete, here is the complete question:

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 5.0 L flask with 2.2 atm of ammonia gas and 2.4 atm of oxygen gas at 44.0°C. He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of nitrogen gas to be 0.99 atm.

Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

Answer: The pressure equilibrium constant for the reaction is 32908.46

Explanation:

We are given

Initial partial pressure of ammonia = 2.2 atm

Initial partial pressure of oxygen gas = 2.4 atm

Equilibrium partial pressure of nitrogen gas = 0.99 atm

The chemical equation for the reaction of ammonia and oxygen gas follows:

$4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(g)$

Initial: 2.2 2.4

At eqllm: 2.2-4x 2.4-3x 2x 6x

Evaluating the value of 'x':

$\Rightarrow 2x=0.99\\\\x=0.495$

So, equilibrium partial pressure of ammonia = (2.2 - 4x) = [2.2 - 4(0.495)] = 0.22 atm

Equilibrium partial pressure of oxygen gas = (2.4 - 3x) = [2.4 - 3(0.495)] = 0.915 atm

Equilibrium partial pressure of water vapor = 6x = (6 × 0.495) = 1.98 atm

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{N_2})^2\times (p_{H_2O})^6}{(p_{NH_3})^4\times (p_{O_2})^3}$

Putting values in above equation, we get:

$K_p=\frac{(0.99)^2\times (1.98)^6}{(0.22)^4\times (0.915)^3}\\\\K_p=32908.46$

Hence, the pressure equilibrium constant for the reaction is 32908.46

5 0

2 years ago

A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated

n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

Step 1: Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

Step 2: Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

Step 3: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

Step 4: Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

Step 5: Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

Step 6: Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

7 0

2 years ago

7. How do the data support your claim above? Explain your statement above. Be sure to refer to specific pieces of data from your

ella [17]

Answer:

if your title doesn't have enough information, make a list of the key words ... If you are not sure what should be included in each summary sentence, use ... Often you can present the hypothesis and the supporting reasoning in one paragraph. ... Describe specific parts of the procedure or data that contributed to your learning.

Explanation:

6 0

2 years ago