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1 year ago

What is the following quotient 3 sqrt 8/ 4 sqrt 6

Mathematics

2 answers:

AnnyKZ [126]1 year ago

8 0

The correct answer is option “D”

adell [148]1 year ago

7 0

We have that
(3√8)/(4√6)

we know that
√8---------> √(2³)-----> 2√2
so
(3√8)/(4√6)=(3*[2√2])/(4√6)---> 6√2/(4√6)
√6=√(2*3)---> √2*√3
6√2/(4√6)=6√2/(4√2*√3)----> 6/(4√3)----> 6/(4√3)*(√3/√3)-----> 6√3/(4*3)----> √3/2

the answer is
√3/2

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Which equation is the inverse of y = 2x2 – 8?

natita [175]

The inverse of the function is $y=\pm \sqrt{\frac{x+8}{2}}$

Explanation:

To find the inverse of the equation $y=2x^{2} -8$ , we need to interchange the variables x and y for the variables y and x.

Thus, the equation becomes

$x=2y^{2} -8$

Now, we shall find the value of y.

Now, adding 8 to both sides of the equation, we have,

$x+8=2y^{2}$

Interchanging the sides,

$2y^{2} =x+8$

Dividing by 2 on both sides,

$y^{2} =\frac{x+8}{2}$

Taking square root on both sides,

$y=\pm \sqrt{\frac{x+8}{2}}$

Thus, the inverse of the function is $y=\pm \sqrt{\frac{x+8}{2}}$

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2 years ago

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adell [148]

Step-by-step explanation:

The Slope is calculated as the change in y over the change in x so you would need to do 5- (-5) which turns the negative sign to a positive making it 5+5=10 and the same thing with the 2s 2-(-2)=4 so the answer would be 10/4 or 5/2. Willa did the reciprocal.

if it's a multiple chose then the answer is b

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7 0

2 years ago

Read 2 more answers

The GPA of accounting students in a university is known to be normally distributed. A random sample of 20 accounting students re

Vladimir79 [104]

Answer:

The 95% of confidence intervals

(2.84 ,2.99)

Step-by-step explanation:

A random sample of 20 accounting students results in a mean of 2.92 and a standard deviation of 0.16

given small sample size n =20

sample mean x⁻ =2.92

sample standard deviation 'S' =0.16

level of significance ∝ = 0.95

The 95% of confidence intervals

$x^{-} ± t_{\alpha } \frac{S}{\sqrt{n} }$

the degrees of freedom γ=n-1 =20-1=19

t-table 2.093

$(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} },x^{-} + t_{\alpha } \frac{S}{\sqrt{n} })$

$(2.92 - 2.093(\frac{0.16}{\sqrt{20} } ,2.92+2.093(\frac{0.16}{\sqrt{20} } )$

(2.92-0.0748,2.92+0.0748)

(2.84 ,2.99)

Therefore the 95% of confidence intervals

(2.84 ,2.99)

4 0

1 year ago

Matt makes $80 a month mowing lawns. His friend James also mows lawns, but he makes x dollars less per month than Matt does. Jam

Ad libitum [116K]

Answer:

he makes $12 less.

Step-by-step explanation:

$80X12=960 - Matts income for the year

960-816=144 -How much less James makes than Matt per year

144/12=12 - How much less James makes than Mat per month

leave 5 stars and a thanks if it was helpful.

3 0

1 year ago

Read 2 more answers

Peter's salary is twice Anne's salary and half of David's salary. Then the average salary of Anne and David is _ of Peter's sala

satela [25.4K]

<h3><u>Answer:</u></h3>

Average of salary of Anne and David is 1.25 of Peter's Salary

<h3><u>Explanation:</u></h3>

In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.

Let us assume Peter's Salary as P.

Then we can calculate Anne's salary A = $\frac{P}{2}$ .

Also David's salary = D = $2 \times P$

Average of Anne's and David's salary = $\frac{A+D}{2}$

Average of Anne's and David's salary = $\frac{\frac{P}{2} + 2 \times P}{2}$

Average of Anne's and David's salary = $\frac{5 \times P}{4}$

Average = 1.25 \times P

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1 year ago