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Eva8 [605]
2 years ago
8

Ali surveyed 200 students at a school and recorded the eye color and the gender of each student. of the 80 male students who wer

e surveyed, 60 had brown eyes. if eye color and gender are independent, how many female students surveyed would be expected to have brown eyes?
Mathematics
1 answer:
Aloiza [94]2 years ago
7 0
Total number of students surveyed = 200
Number of male students = 80
Number of female students = 200 - 80 = 120

Number of brown eyed male students = 60
Probability of a brown eyed male student = 60 / 80 = 0.75.

Since, <span>eye color and gender are independent, this means that eye color is not affected by the gender. Thus, we expect a similar probability of brown eye for female as we had for male.

Let the number expected of brown eyed females be x, then x / 120 = 0.75.

Thus, x = 120(0.75) = 90.

Therefore, the number female students surveyed expected to be brown eyed is 90.</span>
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The green shaded region does not represent the solution to the system of linear inequalities given below. Explain why not.
Sliva [168]

Answer:


Step-by-step explanation:

The area of solutions of the first inequality lies above an orange straight line.

The area of solutions of the second inequality lies below a blue straight line.

These areas are crossed in the yellow field.

The green field does not meet a condition of the second inequality and therefore does not enter the area of the solution of a system of inequalities

7 0
2 years ago
Read 2 more answers
Consider the continuous random variable X, which has a uniform distribution over the interval from 20 to 28.
anastassius [24]

Answer:

a) The probability distribution is f(x) = \frac{1}{8}

b) 0.5 = 50% probability that X will take on a value between 21 and 25.

c) 0.25 = 25% probability that X will take on a value of at least 26.

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{a - x}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

Uniform distribution over the interval from 20 to 28.

This means that a = 20, b = 28

a. What’s the probability density function?

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b - a}

In this question:

f(x) = \frac{1}{28 - 20} = \frac{1}{8}

b. What’s the probability that X will take on a value between 21 and 25?

P(21 \leq X \leq 25) = \frac{25 - 21}{28 - 20} = \frac{4}{8} = 0.5

0.5 = 50% probability that X will take on a value between 21 and 25.

c. What’s the probability that X will take on a value of at least 26?

P(X > 26) = \frac{28 - 26}{28 - 20} = \frac{2}{8} = 0.25

0.25 = 25% probability that X will take on a value of at least 26.

4 0
2 years ago
A single carton of juice costs $4.20. A special offer pack of 3 cartons costs $9.45. Ali bought a special offer pack instead of
fgiga [73]

1 cartons of juice = $4.20

3 single cartons = 4.20 * 3 =  $12.60

1 pack = $9.45

He saved 12.60 - 9.45 = $3.15

So, he saved $3.15, compared to the total ($12.60)

To calculate the percentage, we will do a proportion:

3.15 (money saved) : 12.60 (total of 3 single cartons) = x (how much percentage) : 100 (total)

3.15 : 12.6 = x : 100

To calculate x, we will moltiplicate the ends (where we have known numbers) than divide all per 12.6

So

x = (3.15 * 100) / 12.60 = 315 / 12.6 = 25

So the percentage saving is 25%

6 0
2 years ago
Chelsea is graphing the function f(x) = 20(One-fourth)x. She begins by plotting the initial value. Which graph represents her fi
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Answer:

C

Step-by-step explanation:

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2 years ago
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During the 2010 baseball​ season, the number of wins for three teams was three consecutive integers. Of these three​ teams, the
uysha [10]

Answer:

76075, 76076, 76077

Step-by-step explanation:

<u>There are 3 teams; Team A, Team B and Team C</u>

<em>Team A has most wins</em>

<em>Team C has least wins</em>

<em>Team B is in between</em>

<u>All these will be consecutive numbers.</u>

<em>Team B: x</em>

<em>Team A: x + 1 (most wins)</em>

<em>Team C: x - 1 (least wins)</em>

<em>Team A + Team B + Team C = Total number of wins</em>

x + x + 1 + x - 1 = 228228

3x = 228228

x = 76076

<em>Wins of Team B : x =</em> 76076

<em>Wins of Team A : x + 1 = 76076 + 1 =</em> 76077

<em>Wins of Team C : x - 1 = 76076 - 1 =</em> 76075

Therefore, in the 2010 season, Team A had 76077 wins, Team B had 76076 wins and Team C had 76075 wins.

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