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2 years ago

Does the rule y = 2 · x + 4 represent a linear or an exponential function? Explain.

1 answer:

6 0

B.
Linear function; the independent variable x is not an exponent.

But for me, answer is:

Linear function; the function is in the form y = mx + b, where m = slope, b = y-intercept, and x is a real number.

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Paul has just enough money to buy either 5 erasers and 30 pencils or 10 erasers and 24 pencils. Each eraser costs $0.30. How muc

jasenka [17]

Each pencil will cost $0.25

6 0

2 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

2 years ago

Estimates show that there are 1.4x10^8 pet fish and 9.4x10^6 pet reptiles in the United States. How many pet fish and reptile pe

azamat

Answer:

There are total number of pet fish and reptile pets are $1.49\times 10^8$ .

Step-by-step explanation:

Number of pet fish are $1.4\times 10^8$ and the number of pet reptiles are $9.4\times 10^6$ .

It is required to find the total number of pet fish and reptile pets in the United States. It can be done by simply adding the above numbers such that total numbers are given by :

$T=1.4\times10^{8}+9.4\times10^{6}\\\\T=149400000\\\\T=1.49\times 10^8$