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Finger [1]
2 years ago
7

If the__________ is/are out of balance, the driver will feel a pounding or shaking through the steering wheel.

Computers and Technology
2 answers:
disa [49]2 years ago
8 0

Answer:

Tires

Explanation:

RUDIKE [14]2 years ago
4 0
If the VEHICLE(S) is/are out of balance, the driver will feel a pounding or shaking through the steering wheel.
This pounding <span>shortens the life of all the suspension components and hence</span> <span>produce an uneven tire wear and  which eventually </span>will<span> increase fuel consumption.</span>

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In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation dur
masha68 [24]

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

7 0
2 years ago
Write a destructor for the CarCounter class that outputs the following. End with newline.
ycow [4]

Answer:

Following are the code to this question:

CarCounter::~CarCounter()//Defining destructor CarCounter

{

cout << "Destroying CarCounter\n";//print message Destroying CarCounter

}

Explanation:

Following are the full program to this question:

#include <iostream>//Defining header file

using namespace std;

class CarCounter //Defining class CarCounter

{

public:

CarCounter();//Defining constructor CarCounter

~CarCounter();//Defining destructor CarCounter

private:

int carCount;//Defining integer variable carCount

};

CarCounter::CarCounter()//declaring constructor  

{

carCount = 0;//assign value in carCount variable

return;//using return keyword

}

CarCounter::~CarCounter()//Defining destructor CarCounter

{

cout << "Destroying CarCounter\n";//print message Destroying CarCounter

}

int main() //Defining main method

{

CarCounter* parkingLot = new CarCounter();//Defining class object parkingLot

delete parkingLot;//

return 0;

}

  • In the given C++ language code, a class "CarCounter" is defined, and inside the class, a "constructor, Destructors, and an integer variable" is defined.  
  • Outside the class, the scope resolution operator is used to define the constructor and assign value "0" in the integer variable.  
  • In the above-given code, the scope resolution operator, to define destructor and inside this cout function is used, which prints a message.  
  • In the main method, the class object is created, which automatically calls its class constructor and destructors.  
7 0
2 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to take two strings,
vampirchik [111]

Answer:

Here is the corrected program:

import java.util.Scanner; //to accept input from user

public class 02_14_Activity_one { //class name

    public static void main(String[] args) { //start of main method

    Scanner scan = new Scanner(System.in); //creates Scanner class object

  System.out.println("Enter first string"); //prompts user to enter first string

          String s1 = scan.nextLine(); //reads input string from user

  System.out.println("Enter second string"); //prompts user to enter second string

          String s2 = scan.nextLine(); //reads second input string from user

    System.out.println("Enter number of letters from each word"); //enter n

          int n = scan.nextInt(); //reads value of integer n from user

          System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

         } } //uses substring method to print a string made up of the first n letters of s1 and the last n letters of s2.

Explanation:

The errors were:

1.

Scanner scan = Scanner(System.in);

Here new keyword is missing to create object scan of Scanner class.

Corrected statement:

 Scanner scan = new Scanner(System.in);

2.

String s1 = nextLine();  

Here object scan is missing to call nextLine() method of class Scanner

Corrected statement:

String s1 = scan.nextLine();

3.

String s2 = Scanner.nextLine();

Here class is used instead of its object scan to access the method nextLine

Corrected statement:

String s2 = scan.nextLine();

4.

String n = scan.nextLine();

Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value

Corrected statement:

int n = scan.nextInt();

5.

System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));

This statement is also not correct

Corrected statement:

System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

This works as follows:

s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.

s2.substring(s2.length() - n ) uses substring method to return a new string that is a substring of this s2. The substring then uses length() method to get the length of s2 and subtracts integer n from it and thus returns the last n characters of s2.

The screenshot of program along with its output is attached.

7 0
2 years ago
Go to the Creamy Ice Corporation passage on the next page. Insert the trademark sign after the word “Corporation'' in the first
GuDViN [60]

Answer:

v

Explanation:

because it is

5 0
2 years ago
Complete the program below that takes in one positive, odd, integer, n (at least 3), and prints a "diamond" shape of stars with
avanturin [10]

Answer:

n = int(input("Enter the n (positive odd integer): "))

for i in range(1, n+1, 2):

   print(i*"*")

for i in range(n-2, 0, -2):

   print(i*"*")

Explanation:

*The code is in Python.

Ask the user to enter the n

Create a for loop that iterates from 1 to n, incrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration

Create another for loop that iterates from n-2 to 1, decrementing by 2 in each iteration. Print the corresponding number of asterisks in each iteration

5 0
2 years ago
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