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Mazyrski [523]
2 years ago
6

A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC onto ∆A′B′C′ is a followed by

a .

Mathematics
2 answers:
Eddi Din [679]2 years ago
5 0
The ABC sequence of points is clockwise in both figures, so there will be an even number of reflections or a rotation.

Rotation 90° clockwise about the point (-3, -3) would make the required transformation, but that is not an option. An equivalent is ...
   • reflection across the line x = -3
   • reflection across the line y = x
7nadin3 [17]2 years ago
3 0

Answer:

For Plato the answer is

Blank 1) Rotation 90 degrees  clockwise about the origin

Blank 2) translation 4 units to the right

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Sara wants to find the input value that produces the same output for the functions represented by the tables.
Korolek [52]

Answer:

The input value that produces the same output value in both charts is 2.

Step-by-step explanation:

You are given two functions f(x)=-0.5x+2 and g(x)=2x-3 with tables

\begin{array}{cc}x&f(x)\\-3&3.5\\-2&3\\-1&2.5\\0&2\\1&1.5\\2&1\\3&0.5\end{array}

and

\begin{array}{cc}x&g(x)\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\end{array}

First, fill in the second table:

g(-3)=2\cdot (-3)-3=-6-3=-9\\ \\g(-2)=2\cdot (-2)-3=-7\\ \\g(-1)=2\cdot (-1)-3=-5\\ \\g(0)=2\cdot 0-3=-3\\ \\g(1)=2\cdot 1-3=-1\\ \\g(2)=2\cdot 2-3=1\\ \\g(3)=2\cdot 3-3=3

Hence, the second table is

\begin{array}{cc}x&g(x)\\-3&-9\\-2&-7\\-1&-5\\0&-3\\1&-1\\2&1\\3&3\end{array}

The input value that produces the same output value in both charts is 2.

6 0
2 years ago
Read 2 more answers
Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the following data values: 560,
julsineya [31]

Answer:

z-score for value 560 = 0.6

z-score for value 650 = 1.5

z-score for value 500 = 0

z-score for value 450 = -0.5

z-score for value 300 = -2

Step-by-step explanation:

We are given a sample with a mean of 500 and a standard deviation of 100.

i.e., \mu = 500 and \sigma = 100

The z score distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where X represents the data values;

  • So, z score for value 560 is;

                 z score = \frac{560-500}{100} = 0.6

  • So, z score for value 650 is;

                 z score = \frac{650-500}{100} = 1.5

  • So, z score for value 500 is;

                 z score = \frac{500-500}{100} = 0

  • So, z score for value 450 is;

                 z score = \frac{450-500}{100} = -0.5

  • So, z score for value 300 is;

                 z score = \frac{300-500}{100} = -2

7 0
2 years ago
What is the effect in the time required to solve a problem when you double the size of the input from n to 2n, assuming the numb
kobusy [5.1K]

Answer:

Go to this site

https://www.slader.com/discussion/question/what-is-the-effect-in-the-time-required-to-solve-a-problem-when-you-double-the-size-of-the-input-fro/

there should the your answer

Step-by-step explanation:

3 0
2 years ago
Pls help ima mark BRAINLIST
3241004551 [841]

Answer:

23%

Step-by-step explanation:

There are 30 total students

There are 7 freshman ( 4+3)

P( freshman) = number of freshman/ total

                      =7/30

                       .2333333

                      23.3%

To the nearest whole percent

                     23%

4 0
2 years ago
Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9. Write the division problem
Sveta_85 [38]

Answer:

The required division problem he must solve is:

\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}

Step-by-step explanation:

Consider the provided information.

Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.

As we know that the quotient of the number is a negative number.

Therefore, the sign of both numbers must be different,

Thus we can concluded he must select \frac{2}{3} as one of the card, so that product is a negative number.

Let the selected card be x.

\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}

Hence, the two cards should be \frac{2}{3} and \frac{-3}{8}

The required division problem he must solve is:

\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}

3 0
2 years ago
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