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2 years ago

5

Charlene has a budget of $65. Beau and Belle dresses are $76.48. What inequality can be used to calculate how much of a markdown

Beau and Belle must take for Charlene to stay in her budget

1 answer:

Paraphin [41]2 years ago

6 0

76.48
- 65.00
----------
$11.48
The answer for how much of a markdown would be 15%
The inequality
$76.48 \geqslant 65 + .15$
76.48 is greater than or equal to 65 + 15%

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How many pairs of whole numbers have a sum of 110

kap26 [50]

There are different definitions of "whole numbers".

Some define it as an integer (i.e. positive or negative) [some dictionaries]

Some define it as a non-negative integer. [most math definitions]

We will take the math definition, i.e. 0<= whole number < ∞

To find pairs (i.e. two) whole numbers with a sum of 110, we start with

0+110=110

1+109=110

2+108=110

...

54+56=110

55+55=110

Since the next one, 56+54=110 is the same pair (54,56) as 54+56=110, we stop at 55+55=110 for a total of 56 pairs.

5 0

1 year ago

The table represents the equation y = 2 – 4x. A 2-column table with 5 rows. The first column is labeled x with entries negative

kherson [118]

The missing value for $x=-1$ is $y=6$

Explanation:

It is given that the equation for the table is $y=2-4x$

The table has 2 column with 5 rows.

Thus, we have,

x y

-2 10

-1 ---

0 2

1 -2

2 -6

We need to determine the value of y when $x=-1$

The value of y can be determined by substituting $x=-1$ in the equation $y=2-4x$

Thus, we have,

$y=2-4(-1)$

Multiplying the term within the bracket, we have,

$y=2+4$

Adding the terms, we have,

$y=6$

Thus, the value of y when $x=-1$ is 6.

Hence, the missing value for $x=-1$ is $y=6$

7 0

2 years ago

Read 2 more answers

The time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list

bija089 [108]

Answer:

30, 31, 32, 35, and 38

Step-by-step explanation:

4 0

2 years ago

Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).

Elan Coil [88]

Answer: $\int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV$ = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = $\left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]$ $\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]$

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

$a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0$

Then, replacing with point P and normal vector n:

$36(x-5) + 20(y-0) + 45(z-0) = 0$

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

$z = \frac{180-36x-20y}{45}$

When z = 0:

$y = 9 + \frac{-9x}{5}$

When z=0 and y=0:

x = 5

Then, triple integral is:

$\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx$

Calculating:

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$

$\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}} \, dy } \, dx$

$\frac{1}{45} \int\limits^5_0 {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx$

$\frac{1}{45} \int\limits^5_0 {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4} } \, dx$

$\frac{1}{45} [30375-60750+118462.5-39150]$

$\int\limits^5_0 {\int\limits {\int\ {xyz} \, dy } \, dx$ = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0

2 years ago

mark has a cabinet door in his kitchen with the dimensions shown below. he creates a scale drawing where the width of the cabine

laiz [17]

Answer:

$h^{*} = 25\,in$

Step-by-step explanation:

Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:

$n = \frac{15\,in}{3\,ft}$

$n = 5\,\frac{in}{ft}$

The height of the cabinet is:

$h^{*} = n \cdot h_{door}$

$h_{*} = \left(5\,\frac{in}{ft} \right)\cdot (5\,ft)$

$h^{*} = 25\,in$

6 0

2 years ago

Read 2 more answers