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Inga [223]
2 years ago
12

What is the length of segment AB? Coordinate grid shown from negative 8 to positive 8 on both x axis and y axis at intervals of

1. A straight line labeled AB is drawn. A is the ordered pair 0, 6 and B is the ordered pair 6, 0.
Mathematics
1 answer:
Brums [2.3K]2 years ago
5 0
We can use the pythagorean theorm. This means that the points can form the two legs of a triangle. 

a = 6
b = 6
c = length AB

a^2+b^2 = c^2

2(6^2) = c^2
72 = c^2

c would be \sqrt{72} or 6\sqrt{2}
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Answer:

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Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

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a_2 the horizontal distance between the second observer and the ballonist

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S the area of the triangle formed with the observers and the ballonist

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S=a*h (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

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S_1=a_1*h

But we can write S_1 in terms of \alpha _1, like this:

\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}

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S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})

And replacing in the equation 1:

h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}

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h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

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Step-by-step explanation:

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