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Dmitry_Shevchenko [17]
2 years ago
7

A large coffee urn dispenses coffee at a hospital cafeteria.The cafeteria is open from 6 am until 7 pm daily. The rate at which

coffee is added to the urn is modeled by the function e(x)=3x3+20e(x)=3x3+20 , where the rate is measured in cups of coffee per hour since the cafeteria opened. The rate at which coffee is dispensed from the urn is modeled by the function l(x)=5x2+10l(x)=5x2+10 , where the rate is measured in cups of coffee per hour since the cafeteria opened. What does (e−l)(4) mean in this situation?
A. There are 302 cups of coffee in the urn 4 hours after the cafeteria opened.
B. The rate at which the number of cups of coffee in the urn is changing 4 hours after the cafeteria opened is 302 cups per hour.
C.
There are 122 cups of coffee in the urn 4 hours after the cafeteria opened.
D. The rate at which the number of cups of coffee in the urn is changing 4 hours after the cafeteria opened is 122 cups per hour.
Mathematics
1 answer:
tresset_1 [31]2 years ago
7 0
Think:  Coffee is entering the urn at the same time that coffee is being withdrawn from the urn.  Generally the former rate is greater than the latter, 'tho this is not always the case.  (e - l)(t) signifies the NET amount of coffee in the urn.  If e - l is decreasing, then the amount of coffee there is decreasing.  If e - l is increasing, then the amount of coffee in the urn is increasing, and the urn could eventually overflow.  Please use this info to select the correct answer.

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Answer:

1. Ali makes three straight long cuts along the diameter of the pizza.

2. Ali makes two straight long cuts along the diameter of the pizza.

Step-by-step explanation:

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Statistics can help decide the authorship of literary works. Sonnets by a certain Elizabethan poet are known to contain an avera
tiny-mole [99]

Answer:

We conclude that the sonnets were written by by a certain Elizabethan poet.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 8.9

Sample mean, \bar{x} =10.2

Sample size, n = 6

Alpha, α = 0.05

Population standard deviation, σ = 2.5

First, we design the null and the alternate hypothesis

H_{0}: \mu = 8.88\\H_A: \mu > 8.88

We use One-tailed z test to perform this hypothesis.

a) Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{10.2 - 8.9}{\frac{2.5}{\sqrt{6}} } = 1.28

Now, z_{critical} \text{ at 0.05 level of significance } = 1.64

b) We calculate the p value with the help of z-table.

P-value = 0.1003

The p-value is greater than the significance level which is 0.05

c) Since the p-value is greater than the significance level, there is not enough evidence to reject the null hypothesis and accept the null hypothesis.

Thus, we conclude that the sonnets were written by by a certain Elizabethan poet.

6 0
2 years ago
What did you do to find the GCF given the remaining factors?​
scoray [572]

Answer:

To find GCD or HCF, just write the common factor.

Step-by-step explanation:

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8 0
2 years ago
James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28.
lara31 [8.8K]
Let's use J for James's age and A for Austin's age. The equations are:

J = A - 4
3J + A² = 28

Just plug (A - 4) in the place of J in the second equation. This gives you:

3(A - 4) + A² = 28
-->
A² + 3A - 12 = 28
--> 
A² + 3A - 40 = 0
--> 
(A - 5)(A + 8) = 0
-->
A = 5 or -8

-8 is nonsense, so Austin is 5 years old. Therefore, James is 1 year old.
7 0
2 years ago
Which of the following represents the zeros of f(x) = 5x3 − 6x2 − 59x + 12? (2 points)
Furkat [3]

Answer:

4, −3, 1 over 5

Step-by-step explanation:

x is a zero of f(x) if f(x) = 0

In this problem, we have that:

f(x) = 5x^{3} - 6x^{2} - 59x + 12

4, 3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, 3, − 1 over 5

f(3) = 5*3^{3} - 6*3^{2} - 59*3 + 12 = -84

So 3 is not a zero of the function, and this option is incorrect

4, −3, 1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(\frac{1}{5}) = f(0.2) = 5*(0.2)^{3} - 6*(0.2)^{2} - 59*(0.2) + 12 = 0

So 1 over 5 is a zero of the function

This is the correct answer.

4, −3, −1 over 5

f(4) = 5*4^{3} - 6*4^{2} - 59*4 + 12 = 0

So 4 is a zero of the function

f(-3) = 5*(-3)^{3} - 6*(-3)^{2} - 59*(-3) + 12 = 0

So -3 is a zero of the function

f(-\frac{1}{5}) = f(-0.2) = 5*(-0.2)^{3} - 6*(-0.2)^{2} - 59*(-0.2) + 12 = 23.52

-1 over 5 is not a zero of the function

5 0
2 years ago
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