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harkovskaia [24]
2 years ago
6

EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

Mathematics
2 answers:
Black_prince [1.1K]2 years ago
3 0

Answer:

(C) 10 units

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.

Now, using the Pythagoras theorem in ΔOFG, we have

(FG)^{2}=(OG)^{2}+(OF)^{2}

(FG)^{2}=(8)^{2}+(6)^{2}

(FG)^2=64+36

FG=\sqrt{100}

FG=10

Thus, the value of the side of the rhombus will be 10 units.

Hence, option C is correct.

Oksi-84 [34.3K]2 years ago
3 0

Answer:

C would be the correct answer

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Answer:

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Step-by-step explanation:

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u_{\text{h}} = u \cos \theta = \text{10 m/s} \times \cos 60 ^{\circ} = \text{10 m/s} \times 0.5 = \text{5 m/s}\\u_{\text{v}} = u \sin \theta = \text{10 m/s} \times \sin 60 ^{\circ} = \text{10 m/s} \times 0.866 = \text{8.66 m/s}

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You should place the drain 8.84 m from the pipe.}

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