Answer:
0.6421
Step-by-step explanation:
In this case we have 3 trials and we have 2 options for each one. The driver has or hasn't been under alcohol influence. The probability that the driver has is 0.29 and the probabiility that the driver hasn't is 1 - 0.29 = 0.71
each trial is independent because we are assuming that the population of drivers in between 21 and 25 years old is very big.
The probability that one of them was under alcohol influence can be found by finding the probability that non of them was under alcohol influence because:
1 = p(x = 0) + p(x ≥ 1)
p(x ≥ 1) = 1 - p(0)
The probability that none of them was under alcohol influence is going to be:
0.71×0.71×0.71 = 0.3579
The probability of finding at least one driver that has been under alcohol influence is:
0.6421
Among the choices, the statement which describes a skewed histogram showing a distribution of the weights of students in a class is:
<span>"The nature of the skew can be verified by the position of the mean with respect to the mode."
The histogram is skewed to the right if the mean is less than the mode and the histogram is skewed to the left if the mean is more than the mode. </span><span />
Simple division:
The amount/number of seconds=amount per second.
1000/10=100
Lightning strikes earth 100 times per second.
Answer:
Part 1)
See Below.
Part 2)

Step-by-step explanation:
Part 1)
The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

We want to verify that the expression:

Is the linear approximation for the function:

At <em>x</em> = 0.
So, find f'(x). We can use the chain rule:

Simplify. Hence:

Then the slope of the linear approximation at <em>x</em> = 0 will be:

And the value of the function at <em>x</em> = 0 is:

Thus, the linear approximation will be:

Hence verified.
Part B)
We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.
In other words:

By definition:

Therefore:

We can solve this by using a graphing calculator. Please refer to the graph shown below.
We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.
In interval notation:
