Answer:
The options
A. the postzygotic barrier called hybrid inviability
B. the postzygotic barrier called hybrid breakdown
C. the prezygotic barrier called hybrid sterility
D. gametic isolation
The CORRECT ANSWER IS A.
A. the postzygotic barrier called hybrid inviability
Explanation:
Postzygotic barrier is a mechanism that hinders reproduction after fertilization and zygote development. Hybrid inviability occurs when a mating between two organism produces a hybrid that can't strive past the embryonic stages.
In Reduced Hybrid Viability there is a lower tendency to survive for individuals whose parents possesses incompatible genetics, which may have result from sexual union of these parents from varying species.
These two frog species in this case study can be separated through the mechanism of the postzygotic barrier called hybrid inviability.
Answer:
Glucose utilization would increase a lot.
Explanation:
Aerobic condition indicates the presence of large amount of oxygen in the body. Anaerobic condition means that the oxygen is limited or deficient in the body.
The muscle cells shows anaerobic condition during exercise and produces lactic acid. Since, the ATP demand is same in both the aerobic and anaerobic conditions. This increases the demand of glucose in the body. Glucose utilization is increased to provide proper energy to the individual.
Thus, the correct answer is option (a).
Answer: Survival rate up to start of April = 76.67%
Explanation: size of colony = 150mice.
Size of colony in February =125mice.
Size of colony in march = 115 mice.
1. Survivorship rate in February
= Size of colony / size in February *100.
= 122 / 150 * 100
= 83.33% to the nearest hundredth
2. Survivorship rate in march
= Size of colony / size in march *100.
= 115/150 * 100
= 76.67% to the nearest hundredth.
You would the find the greatest diversity of species in a temperate kelp forest.
I hope this helps.
They would have to use micro dissection instruments
