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2 years ago

9

Which statement is true of triangles QRS and MNP?

1 answer:

Nimfa-mama [501]2 years ago

4 0

The answer is b.
We can do the process of elimination:
We know it's not "a" since all the sides are different.
"B" states that the traingles are similar and "c" states that the traingles are not similar. The angles are the same, which means that the traingles are indeed similar (AA theorem). This eliminates "c", which leaves you with "b".

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A kite has a perimeter of 70 centimeters. One of the shorter sides measures 16 centimeters. What are the lengths of the other th

kari74 [83]

Answer:

a kite has 2 short sides and 2 long sides. The 2 short sides are equal. The 2 long sides are also equal. This means that the other short side is 16cm. And the remaining longer sides can be found like this:

let's pretend *y* is the long side

2*y = 70 - 16 - 16. (two of the long sides = 70 - short side - another short side)

so use algebra to find y.

2*y = 38

y = 19 so the long sides are both 19cm each

Your final answer: 16cm, 19cm, 19cm

5 0

2 years ago

Read 2 more answers

Suppose that a company's sales were $1,000,000 6 years ago and are $9,000,000 at the end of the 6 years. Find the geometric mean

Dmitriy789 [7]

Answer:

The geometric mean growth rate of sales is 1.4422.

Step-by-step explanation:

We have two sales values, one from 6 years ago and the other from now.

We have to calculate the geometric growth rate of sales.

We have:

$y(-6)=1,000,000\\\\y(0)=9,000,000$

We can write the relation between these two values as:

$y(0)=y(-6)k^{0-(-6)}\\\\9,000,000=1,000,000k^6\\\\k^6=9\\\\k=9^{1/6}= 1.4422$

The geometric mean growth rate of sales is 1.4422.

6 0

2 years ago

Which of the following assessment types has the greatest effect on your overall grade?

frutty [35]

I’m pretty sure the answer is test

3 0

2 years ago

A charity organization had to sell 18 tickets to their fundraiser just to cover necessary production costs.

meriva

Answer: slope and x-intercept

4 0

2 years ago

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A pendulum is set swinging. its first oscillation is through 30 and each succeeding oscillation is through 95% of the angle of t

Marat540 [252]

<u>Answer-</u>

<em>After 76 swings</em><em> the angle through which it swings less than 1°</em>

<u>Solution-</u>

From the question,

Angle of the first of swing = 30° and then each succeeding oscillation is through 95% of the angle of the one before it.

So the angle of the second swing = $(30\times \frac{95}{100})^{\circ}$

Then the angle of third swing = $(30\times (\frac{95}{100})^2)^{\circ}$

So, this follows a Geometric Progression.

$(30,\ 30\cdot \frac{95}{100},\ 30\cdot (\frac{95}{100})^2............,0)$

a = The initial term = 30

r = Common ratio = $\frac{95}{100}$

As we have to find the number swings when the angle swept by the pendulum is less than 1°.

So we have the nth number is the series as 1, applying the formula

$T_n=ar^{n-1}$

Putting the values,

$\Rightarrow 1=30(\frac{95}{100})^{n-1}$

$\Rightarrow \frac{1}{30} =(\frac{95}{100})^{n-1}$

Taking logarithm of both sides,

$\Rightarrow \log \frac{1}{30} =\log (\frac{95}{100})^{n-1}$

$\Rightarrow \log \frac{1}{30} =(n-1)\log (\frac{95}{100})$

$\Rightarrow -1.5=(n-1)(-0.02)$

$\Rightarrow 1.5=(n-1)(0.02)$

$\Rightarrow n-1=\dfrac{1.5}{0.02}$

$\Rightarrow n-1=75$

$\Rightarrow n=76$

Therefore, after 76 swings the angle through which it swings less than 1°

8 0

2 years ago